part (a) and (b) The image depicts a section of an educational interface for solving physics problems. It includes a problem statement and input areas for calculations. The problem is divided into several parts, and part (a) is highlighted:### Problem Part (a)- **Task:** Find the work done, in joules (J), by the normal force exerted by the ground.- **Equation Input Box:** Appears with a placeholder "W =" followed by a blank box where the answer should be entered in joules.### Calculator Interface- **Functions Available:** - Trigonometric: `sin()`, `cos()`, `tan()` - Inverse Trigonometric: `asin()`, `acos()`, `atan()` - Hyperbolic: `sinh()`, `cosh()`, `tanh()` - Others: `cotan()`, `acotan()`, `coth()`, `cotanh()`- **Radial Option:** Choose between `Degrees` or `Radians`.### Numerical Keypad- Buttons for numbers (0-9), basic arithmetic operations (`+`, `-`, `*`, `/`), and constants like `π`.### Additional Options- **Controls:** - `Submit`: To send the answer for evaluation. - `Hint`, `Feedback`, and an option called `I give up!` for further assistance or to quit the problem.### Problem Parts (b), (c), and (d)- **Part (b):** Find the work done, in J, by the applied force.- **Part (c):** Find the work done, in J, by the force of gravity.- **Part (d):** Find the work done, in J, by the force of friction.This interface is part of a physics learning platform, assisting students in understanding and calculating work done by various forces. **Problem 2:**A 32 kg block is pulled along the ground for a distance of 5.2 m by a 63 N force at an angle of 18 degrees with respect to the horizontal. The coefficient of kinetic friction is 0.25.**Part (a):** Find the work done, in joules (J), by the normal force exerted by the ground.\[ W = \text{______ J} \]**Diagram:**- The image shows a block on a horizontal surface with a force vector directed at an angle to the surface, representing the pulling force exerted on the block.**Calculator Inputs:**- Function buttons available: sin(), cos(), tan(), cotan(), asin(), acos(), atan(), acotan(), sinh(), cosh(), tanh(), cotanh()- A numeric keypad for entering values- Option to select between Degrees and Radians for angle inputButtons at the bottom include: Submit, Hint, Feedback, and I give up!

Formula of work done is as follows; W=Fdcosθ 1)where,F=forced=displacementθ=Angle between force and displacement where, Fa=applied forceFf=force of frictionN=Normal forcem=mass of blockθ=Anglea=acceleration of blockValues given in the question are as follow; Fa=63 Nd=5.2 mm=32 kgθ=18° From the free body diagram of block, Angle between normal force and displacement is θ=90° we know that, cos90°=0 Hence, work done by normal force is Zero.Work done by normal force is as follows; W=Fadcosθ Substitute known values in above equation: W=63×5.2 ×cos18°W=311.57 J Work done by applied force is 311.57 J

Answered: Problem 2: A 32 kg block is pulled…

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Physics

Problem 2: A 32 kg block is pulled along the ground for a distance of 5.2 m by a 63 N force at an angle of 18 degrees with respect to the horizontal. The coefficient of kinetic friction is 0.25.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

part (a) and (b)

The image depicts a section of an educational interface for solving physics problems. It includes a problem statement and input areas for calculations. The problem is divided into several parts, and part (a) is highlighted:

### Problem Part (a)
- **Task:** Find the work done, in joules (J), by the normal force exerted by the ground.
- **Equation Input Box:** Appears with a placeholder "W =" followed by a blank box where the answer should be entered in joules.

### Calculator Interface
- **Functions Available:**
- Trigonometric: `sin()`, `cos()`, `tan()`
- Inverse Trigonometric: `asin()`, `acos()`, `atan()`
- Hyperbolic: `sinh()`, `cosh()`, `tanh()`
- Others: `cotan()`, `acotan()`, `coth()`, `cotanh()`
- **Radial Option:** Choose between `Degrees` or `Radians`.

### Numerical Keypad
- Buttons for numbers (0-9), basic arithmetic operations (`+`, `-`, `*`, `/`), and constants like `π`.

### Additional Options
- **Controls:**
- `Submit`: To send the answer for evaluation.
- `Hint`, `Feedback`, and an option called `I give up!` for further assistance or to quit the problem.

### Problem Parts (b), (c), and (d)
- **Part (b):** Find the work done, in J, by the applied force.
- **Part (c):** Find the work done, in J, by the force of gravity.
- **Part (d):** Find the work done, in J, by the force of friction.

This interface is part of a physics learning platform, assisting students in understanding and calculating work done by various forces.

**Problem 2:**

A 32 kg block is pulled along the ground for a distance of 5.2 m by a 63 N force at an angle of 18 degrees with respect to the horizontal. The coefficient of kinetic friction is 0.25.

**Part (a):** Find the work done, in joules (J), by the normal force exerted by the ground.

\[ W = \text{______ J} \]

**Diagram:**

- The image shows a block on a horizontal surface with a force vector directed at an angle to the surface, representing the pulling force exerted on the block.

**Calculator Inputs:**

- Function buttons available: sin(), cos(), tan(), cotan(), asin(), acos(), atan(), acotan(), sinh(), cosh(), tanh(), cotanh()
- A numeric keypad for entering values
- Option to select between Degrees and Radians for angle input

Buttons at the bottom include: Submit, Hint, Feedback, and I give up!

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