b) Find the magnitude R of resultant force R. c) Find Rx ad Ry components of the resultant force R.
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- F, = 500N 35 F = 600N F, = 200N a) Find the resultant force vector R. (you can use "paint" to indicate and draw the resultant force vector R) b) Find the magnitude R of resultant force R. c) Find Rx ad Ry components of the resultant force R.2. Determine the following: a) Magnitude of the projected component of along the line of action of F2 b) Angle 0 between the two cables attached to the pipe. F, = MN Ib 120 60° F, = SN Ib 1.5 m 3. The guy wires are used to support the telephone pole. Represent the force in each wire in Cartesian vector form. Neglect the diameter of the pole F= MNN F: = FN N 4 m 2 m D. 4 m 3 m yiv )Determine the angle of the resultant force, FR (answer in degree) v) Determine the total moments created by the force components about point 0. ( answer in newton meter)
- Answer the following. 1.) Determine the resultant force if F1 = 120 lb at 60 deg N of W, F2 = 100 lb southeast. 2.) Find the magnitude of the resultant force if F1 = 50 lb at 35 deg S of W and F2 = 40 lb at 25 deg N of W.Replace the force system by a single force resultant and specify its point of application, measured along the x axis from point P. Given: Fj = 125 N a = 1 m F2 = 350 N b = 3 m F2 F3 = 850 N c = 1.5 m d = 2 m a 1) Find FCR) = N. (+ Point up point down] 2) find distance bet ween FrR) and PQ2: The shaft S exerts three force components on the die D. Find the magnitude and coordinate direction angles of the resultant force. Force F, acts within the octant shown. F 200 N Y2 60 F= 300 N = 60 F = 400 N
- Determine the magnitude of the resultant of the system of concurrent forces having the following magnitudes and passing through the origin and the indicated points: P=520 lb (+8,-6,+5), T=270 lb (-3,-4, +10), F=280 lb (+5,-3,-6). a.) 273.272 lb b.) 476.065 lb c.) 466.966 lb d.) 720.675 lb e.) None of the aboveQ3. For the force system shown in the figure. Determine the following: a) The magnitude of the resultant of the forces, F₁, F2, and F3. b) The angle between F₁ and F₂. c) The magnitude of the moment of the force F₁ about point O. d) The moment of the force F₁ about line OC in Cartesian vector form. 80 mm 180 mm X F₂ = 600 N 45° 250 mm F₁ = 700 N B 120° F₁-800 N 180 mm 160 mmQ1: a) Find the vector expression for F on AD, b) Find its projection along AC. 3 m D B A T=4.2 KN 5 m 2 m 1m
- Q1) For the force system shown in figure, 1) Find the angle (4) so that the resultant of these forces will be vertical. 55 kN 45 kN В A |C 3 m 1m 3 mQ.1) Replace the given force system by a resultant force system acting at point A. Then replace the resultant force system by the simplest resultant (a single force) and find x and y intercepts of its line of action from point A. 60 lb 15" 10" y 90 lb A 9" B -DE 120 lb-in. 12" X G 12" 70 lb 10" F 80 lbQ2: Determine the resultant of the force system in next fig. Then locate it with respect to point (A). 1000 N.m 80 N 10m 150 N 10M 100 N l0m