(b) Compute an 88.9% Chebyshev interval around the population mean. Recall that Chebyshev's Theorem states that for any set of data and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least 1 - Therefore, for data with mean u and standard deviation o, at least 1 – of data must fall between u- ko and + ko. When k- 3, we have the following. 1. or 88.9% Therefore, for any set of data, at least 88.9% of the data must fall between - 3a and or, in other words, within standard deviations of the mean.

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(b) Compute an 88.9% Chebyshev interval around the population mean.
Recall that Chebyshev's Theorem states that for any set of data and for any constant k greater than 1, the
proportion of the data that must lie within k standard deviations on either side of the mean is at least 1 -
Therefore, for data with mean u and standard deviation a, at least 1 -
of data must fall between u- ko
and + ko.
When k- 3, we have the following.
1-
1
or 88.9%
Therefore, for any set of data, at least 88.9% of the data must fall between - 3a and
or, in other words, within
standard deviations of the mean.
Transcribed Image Text:(b) Compute an 88.9% Chebyshev interval around the population mean. Recall that Chebyshev's Theorem states that for any set of data and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least 1 - Therefore, for data with mean u and standard deviation a, at least 1 - of data must fall between u- ko and + ko. When k- 3, we have the following. 1- 1 or 88.9% Therefore, for any set of data, at least 88.9% of the data must fall between - 3a and or, in other words, within standard deviations of the mean.
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