14. What is the test statistic and its distribution for the hypothesis test stated in the preamble of Section D?XμlO ZZ~ N (0, 1)o/√nOT:Ď HDSD/√nT~t35OZP-Pp(1-p)Z~ N (0,1)nX-μlOT=S/√√n=---"""2T t35 Section D: A research team believes that the systolic blood pressure of adult males is normally distributed with apopulation variance equal to 400. A simple random sample of 36 males selected from the adult male population had amean systolic blood pressure reading of 130. Let u denote the mean systolic blood pressure of adult males. Suppose theresearch team wants to test, at the 5% level of significance, whether the mean systolic blood pressure of adult males isnot equal to 135. Suppose the assumptions of this hypothesis test are satisfied.

The question is about identifying the hypo. tests Given : Popl. variance of systolic blood pressure…

Answered: 14. What is the test statistic and its…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An independent random sample is selected from an approximately normal population with an unknown standard deviation. Find the p-value for the given sample size and test statistic. Also determine if the null hypothesis would be rejected at α = 0.05. For each the given set of hypotheses, sample size and the T-statistic,find the p-value, draw a t-curve and shade the region of which the area the p-value indicates. As it’s notpossible to find the precise P-values using a t-table, it suffices to give a range. (a) HA : μ 6= 0.5, n = 26, T = 2.6(b) HA : μ < 3, n = 18, T = −2.2(c) HA : μ < 3, n = 18, T = 2.2
To test Upper H 0H0: muμequals=20 versus Upper H 1H1: muμless than<20, a simple random sample of size nequals=18 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d). (a) If x overbarxequals=18.3 and sequals=4.5, compute the test statistic. tequals=nothing (Round to two decimal places as needed.)
Consider a population of values described by X ~ N(20, 92) For a specific sample of size n = 15, we have X-bar = 22.4. Find the Z-score for the X-bar value.
23. In a test of hypotheses Ho u = 456 versus H1 : µ < 456, the rejection region is the interval (-00, -1.796], the value of the sample mean computed from a sample of size 12 is = 453, and the value of the test statistic is t = -2.598. The correct decision and justification are: %3D %3D %3D HoM=U56 Hi MLUS6C larim (a) Do not reject Ho because the sample is small. (b) Do not reject Ho because -2.598 < -1.796. (c) Reject Ho because 453 is less than 456. LOS a=.0S (d) Reject H because -2.598 is negative. Ae) Reject Ho because -2.598 lies in the rejection region.
The pressure of air (in MPa) entering a compressor is measured to be X = 8.5 ± 0.2, and the pressure of the air leaving the compressor is measured to be Y = 21.2 ± 0.3. The intermediate pressure is therefore measured to be P = √XY = 13.42 . Assume that X and Y come from normal populations and are unbiased. a) From what distributions is it appropriate to simulate values X* and Y*? b) Generate simulated samples of values X*, Y*, and P*. c) Use the simulated sample to estimate the standard deviation of P. d) Construct a normal probability plot for the values P*. Is it reasonable to assume that P is approximately normally distributed? e) If appropriate, use the normal curve to find a 95% confidence interval for the intermediate pressure.
If we assume that the distribution of means is normal, then 95% of all sample means a) will fall in the interval m ± 1.96(σm) b) will fall in the interval m ± 1.645(σm) c) will be no more than 1.645(σm) from μ d) will be no more than from 1.96(σm) from μ
In a test of HO: μ-25 against HA: μ # 25, a sample of size 125 produces Z = 1.28 for the value of the test statistic. What is the p-value equal to? Use four decimal places. Do not show any work.
3) Suppose test scores are measured by the Gaussian Normal Distribution N(X,75,10) calculate the following. a) Pr(80 < X < 90) b) Pr(50 < X < 70) c) The 95 th percentile
You may need to use the appropriate appendix table or technology to answer this question. Given are five observations for two variables, x and y. (Round your answers to two decimal places.) xi 1 2 3 4 5 yi 4 8 5 11 15 (a) Use sŷ* = s 1 n + (x* − x)2 Σ(xi − x)2 to estimate the standard deviation of ŷ* when x = 5. (b) Use ŷ* ± t?/2sŷ* to develop a 95% confidence interval for the expected value of y when x = 5. to (c) Use spred = s 1 + 1 n + (x* − x)2 Σ(xi − x)2 to estimate the standard deviation of an individual value of y when x = 5. (d) Use ŷ* ± t?/2spred to develop a 95% prediction interval for y when x = 5. to I need all the parts, I attached a picture of the whole question in case the one I copied above was not clear enough.
b) Find the mean and standard deviation of the difference. c) Find the rejection region and state your decision at α = 0.01.
A mixture of pulverized fuel ash and Portland cement to be used for grouting should have a compressive strength of more than 1,300 KN/m2. The mixture will not be used unless experimental evidence indicates conclusively that the strength specification has been met. Suppose compressive strength for specimens of this mixture is normally distributed with o = 69. Let u denote the true average compressive strength. (a) What are the appropriate null and alternative hypotheses? O Ho: H > 1,300 H: u = 1,300 Ο H,: μ= 1,300 H: u 1,300 (b) Let X denote the sample average compressive strength for n = 15 randomly selected specimens. Consider the test procedure with test statistic X itself (not standardized). What is the probability distribution of the test statistic when Ho is true? O The test statistic has a binomial distribution. O The test statistic has a gamma distribution. The test statistic has a normal distribution. O The test statistic has an exponential distribution. If X = 1,340, find the…

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14. What is the test statistic and its distribution for the hypothesis test stated in the preamble of Section D? X - μl OZ Z ~ N (0, 1) o/√√n OT= D-HD SD/√n 2 Р - P O Z= p(1-p) n OT= X-μ S/√√n = 2 2 " T~ t35 Z~ N (0,1) T~ t35