a test of hypotheses Ho : H = -27 versus Ha : u # -27 in a normally distributed population, e rejection region is the union of intervals (-oo, -2.120] U [2.120, o0), the value of the sample mean mputed from a sample of size 17 is i = -28.5, and the value of the test statistic is t = -2.811. The rect decision and justification are: %3D ) Do not reject Ho because the sample is small. ) Do not reject Ho because -28.5 lies in the rejcction region. c) Reject Ho because = -28.5 -27 = Ho. 1) Reject Ho because the test statistic is negative. e) Reject Ho because -2.811 < -2.120.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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In a test of hypotheses \( H_0: \mu = -27 \) versus \( H_a: \mu \neq -27 \) in a normally distributed population, the rejection region is the union of intervals \((-\infty, -2.120) \cup [2.120, \infty)\). The value of the sample mean computed from a sample of size 17 is \( \bar{x} = -28.5 \), and the value of the test statistic is \( t = -2.811 \). The correct decision and justification are:

(a) Do not reject \( H_0 \) because the sample is small.

(b) Do not reject \( H_0 \) because \(-28.5\) lies in the rejection region.

(c) Reject \( H_0 \) because \( \bar{x} = -28.5 \neq -27 = \mu_0 \).

(d) Reject \( H_0 \) because the test statistic is negative.

(e) Reject \( H_0 \) because \(-2.811 < -2.120\).
Transcribed Image Text:In a test of hypotheses \( H_0: \mu = -27 \) versus \( H_a: \mu \neq -27 \) in a normally distributed population, the rejection region is the union of intervals \((-\infty, -2.120) \cup [2.120, \infty)\). The value of the sample mean computed from a sample of size 17 is \( \bar{x} = -28.5 \), and the value of the test statistic is \( t = -2.811 \). The correct decision and justification are: (a) Do not reject \( H_0 \) because the sample is small. (b) Do not reject \( H_0 \) because \(-28.5\) lies in the rejection region. (c) Reject \( H_0 \) because \( \bar{x} = -28.5 \neq -27 = \mu_0 \). (d) Reject \( H_0 \) because the test statistic is negative. (e) Reject \( H_0 \) because \(-2.811 < -2.120\).
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