B are defined on a common sample D30.56, find P(A and B).

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**Problem Statement:**

14. Events \( A \) and \( B \) are defined on a common sample space. If \( P(A) = 0.20 \), \( P(B) = 0.40 \), and \( P(A \text{ or } B) = 0.56 \), find \( P(A \text{ and } B) \).

**Explanation:**

To solve this problem, we need to use the formula for the probability of the union of two events:

\[ P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \]

Given:
- \( P(A) = 0.20 \)
- \( P(B) = 0.40 \)
- \( P(A \text{ or } B) = 0.56 \)

Plugging into the formula:

\[ 0.56 = 0.20 + 0.40 - P(A \text{ and } B) \]

Solve for \( P(A \text{ and } B) \):

\[ 0.56 = 0.60 - P(A \text{ and } B) \]
\[ P(A \text{ and } B) = 0.60 - 0.56 \]
\[ P(A \text{ and } B) = 0.04 \]

Therefore, the probability that both events \( A \) and \( B \) occur is \( P(A \text{ and } B) = 0.04 \).
Transcribed Image Text:**Problem Statement:** 14. Events \( A \) and \( B \) are defined on a common sample space. If \( P(A) = 0.20 \), \( P(B) = 0.40 \), and \( P(A \text{ or } B) = 0.56 \), find \( P(A \text{ and } B) \). **Explanation:** To solve this problem, we need to use the formula for the probability of the union of two events: \[ P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \] Given: - \( P(A) = 0.20 \) - \( P(B) = 0.40 \) - \( P(A \text{ or } B) = 0.56 \) Plugging into the formula: \[ 0.56 = 0.20 + 0.40 - P(A \text{ and } B) \] Solve for \( P(A \text{ and } B) \): \[ 0.56 = 0.60 - P(A \text{ and } B) \] \[ P(A \text{ and } B) = 0.60 - 0.56 \] \[ P(A \text{ and } B) = 0.04 \] Therefore, the probability that both events \( A \) and \( B \) occur is \( P(A \text{ and } B) = 0.04 \).
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