(b) A simple way would be as follows. Let z=t, where 2
Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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hi, i got the workings and explaination already, but i have no idea whats going on at all, please help to explain ! such as sin and cos where did it come from, and how should i cope with this type of questions should i ever face them
![(b) A simple way would be as follows. Let z=t, where 2<t<9. It follows that
x + y = t-1. We can then choose x= \t-1cos(u) and y= Vt-1sin(1) , where u
is another free parameter. Thus, a parametric representation for the surface is given by
x= Vt-1 cos(u),
y= \t-1sin(u) '} for 2<t<9.
Z= t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe594dc0-2b5b-4bcb-9d92-f82cc2a5b645%2F2f72b291-2a41-48c9-a13d-d423a7a35a05%2Fym3zw4k_processed.png&w=3840&q=75)
Transcribed Image Text:(b) A simple way would be as follows. Let z=t, where 2<t<9. It follows that
x + y = t-1. We can then choose x= \t-1cos(u) and y= Vt-1sin(1) , where u
is another free parameter. Thus, a parametric representation for the surface is given by
x= Vt-1 cos(u),
y= \t-1sin(u) '} for 2<t<9.
Z= t
![(b) 1+ x² + y –z = 0 for 2< z<9.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe594dc0-2b5b-4bcb-9d92-f82cc2a5b645%2F2f72b291-2a41-48c9-a13d-d423a7a35a05%2F19b61pt_processed.png&w=3840&q=75)
Transcribed Image Text:(b) 1+ x² + y –z = 0 for 2< z<9.
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