#3 Sin (345 degrees)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question
#3
Sin (345 degrees)
![The image contains handwritten trigonometric calculations, primarily involving tangent functions. Here is the transcription of the text:
---
**Problem 2:**
\[
\tan(40^\circ) - \tan(10^\circ) \over 1 + \tan(40^\circ)\tan(10^\circ)
\]
- The calculation appears to involve the formula for the tangent of the difference of two angles: \(\tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}\).
\[
\tan(40^\circ - 10^\circ) = \frac{\tan(40^\circ) - \tan(10^\circ)}{1 + \tan(40^\circ)\tan(10^\circ)}
\]
There seems to be a simplification process, or potentially a calculation leading to an approximate result:
- \(\tan(30^\circ)\ = \frac{1}{\sqrt{3}}\)
The calculation aims to simplify or approximate the values using known trigonometric identities.
**Problem 3:**
- Appears to be a separate calculation:
\[
5.7 \times (3.45)
\]
---
No graphs or diagrams are present in the image. The calculations rely on understanding the tangent difference identity and basic multiplication.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F085e24e4-6db3-44bd-bedd-407e7fcd33ea%2Fbebf0163-9e8f-4351-9411-85d8e557e205%2Fe815p5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The image contains handwritten trigonometric calculations, primarily involving tangent functions. Here is the transcription of the text:
---
**Problem 2:**
\[
\tan(40^\circ) - \tan(10^\circ) \over 1 + \tan(40^\circ)\tan(10^\circ)
\]
- The calculation appears to involve the formula for the tangent of the difference of two angles: \(\tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}\).
\[
\tan(40^\circ - 10^\circ) = \frac{\tan(40^\circ) - \tan(10^\circ)}{1 + \tan(40^\circ)\tan(10^\circ)}
\]
There seems to be a simplification process, or potentially a calculation leading to an approximate result:
- \(\tan(30^\circ)\ = \frac{1}{\sqrt{3}}\)
The calculation aims to simplify or approximate the values using known trigonometric identities.
**Problem 3:**
- Appears to be a separate calculation:
\[
5.7 \times (3.45)
\]
---
No graphs or diagrams are present in the image. The calculations rely on understanding the tangent difference identity and basic multiplication.
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