b-a on and interval. Round to the nearest thous 3] 523

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Mean Value Theorem Application**

**Problem Statement:**
Find the value or values of \( c \) that satisfy the equation 

\[
\frac{f(b) - f(a)}{b - a} = f'(c)
\]

in the conclusion of the Mean Value Theorem for the given function and interval. Round to the nearest thousandth.

**Given:**

\[
f(x) = \tan^{-1}x, \quad \left[ -\sqrt{3}, \sqrt{3}\right]
\]

**Options:**
- A. \(-0.523, 0, 0.523\)
- B. \(0.523\)
- C. \(0, 0.523\)
- D. \(\pm 0.523\)

**Instructions:**
Select the correct answer that corresponds to the value or values of \( c \) that satisfy the equation.

---

In this problem, you are working with the Mean Value Theorem to find specific values of \( c \) in the interval \(\left[ -\sqrt{3}, \sqrt{3}\right]\) where the derivative of the function equals the average rate of change over the entire interval.

**Graph Explanation:**
Although this problem does not come with a graph or diagram, if there were one, it would typically illustrate the function \( f(x) = \tan^{-1}x \) over the interval \(\left[ -\sqrt{3}, \sqrt{3}\right]\). The graph would show the secant line from \((-\sqrt{3}, f(-\sqrt{3}))\) to \((\sqrt{3}, f(\sqrt{3}))\) and the tangent line at \( x = c \) where the slope of the tangent is equal to the slope of the secant line. It would also help visualize the value of \( f(x) \) and its derivative at the specific points.

---

**Answer**: Please select the value from the options that corresponds with the conditions stated in the Mean Value Theorem.
Transcribed Image Text:--- **Mean Value Theorem Application** **Problem Statement:** Find the value or values of \( c \) that satisfy the equation \[ \frac{f(b) - f(a)}{b - a} = f'(c) \] in the conclusion of the Mean Value Theorem for the given function and interval. Round to the nearest thousandth. **Given:** \[ f(x) = \tan^{-1}x, \quad \left[ -\sqrt{3}, \sqrt{3}\right] \] **Options:** - A. \(-0.523, 0, 0.523\) - B. \(0.523\) - C. \(0, 0.523\) - D. \(\pm 0.523\) **Instructions:** Select the correct answer that corresponds to the value or values of \( c \) that satisfy the equation. --- In this problem, you are working with the Mean Value Theorem to find specific values of \( c \) in the interval \(\left[ -\sqrt{3}, \sqrt{3}\right]\) where the derivative of the function equals the average rate of change over the entire interval. **Graph Explanation:** Although this problem does not come with a graph or diagram, if there were one, it would typically illustrate the function \( f(x) = \tan^{-1}x \) over the interval \(\left[ -\sqrt{3}, \sqrt{3}\right]\). The graph would show the secant line from \((-\sqrt{3}, f(-\sqrt{3}))\) to \((\sqrt{3}, f(\sqrt{3}))\) and the tangent line at \( x = c \) where the slope of the tangent is equal to the slope of the secant line. It would also help visualize the value of \( f(x) \) and its derivative at the specific points. --- **Answer**: Please select the value from the options that corresponds with the conditions stated in the Mean Value Theorem.
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