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If ả = (–4, −8) and ☎ = (–2, −6), find |2.5ả – 36|. O 20 O 2√5 O-6 O 4√2

If ả = (–4, −8) and ☎ = (–2, −6), find |2.5ả – 36|. O 20 O 2√5 O-6 O 4√2

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter9: Real Numbers And Right Triangles
Section9.5: The Distance And Midpoint Formulas
Problem 2C
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Given: - Vector \(\mathbf{a} = \langle -4, -8 \rangle\) - Vector \(\mathbf{b} = \langle -2, -6 \rangle\) Find the magnitude of \(2.5\mathbf{a} - 3\mathbf{b}\). Options to choose from: 1. \(20\) 2. \(2\sqrt{5}\) 3. \(-6\) 4. \(4\sqrt{2}\) To find the correct answer, one needs to: 1. Calculate the expressions \(2.5\mathbf{a}\) and \(3\mathbf{b}\). 2. Subtract \(3\mathbf{b}\) from \(2.5\mathbf{a}\) to get the resultant vector. 3. Determine the magnitude of the resultant vector.
Transcribed Image Text:Given: - Vector \(\mathbf{a} = \langle -4, -8 \rangle\) - Vector \(\mathbf{b} = \langle -2, -6 \rangle\) Find the magnitude of \(2.5\mathbf{a} - 3\mathbf{b}\). Options to choose from: 1. \(20\) 2. \(2\sqrt{5}\) 3. \(-6\) 4. \(4\sqrt{2}\) To find the correct answer, one needs to: 1. Calculate the expressions \(2.5\mathbf{a}\) and \(3\mathbf{b}\). 2. Subtract \(3\mathbf{b}\) from \(2.5\mathbf{a}\) to get the resultant vector. 3. Determine the magnitude of the resultant vector.
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