b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ < 1/\z|. Let C be the closed contour along the boundary of the square with sides 1 = ±3 and y = ±3 (see the screen) Prove that zf(z) dz = 0.
b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ < 1/\z|. Let C be the closed contour along the boundary of the square with sides 1 = ±3 and y = ±3 (see the screen) Prove that zf(z) dz = 0.
b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ < 1/\z|. Let C be the closed contour along the boundary of the square with sides 1 = ±3 and y = ±3 (see the screen) Prove that zf(z) dz = 0.
From a calculus course focused on complex numbers and variables. Has to do with the principle of deformation of paths
Transcribed Image Text:b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ <1/\z®. Let C be the
closed contour along the boundary of the square with sides I = ±3 and y = ±3 (see the screen)
Prove that f zf(z) dz = 0.
Combination of a real number and an imaginary number. They are numbers of the form a + b , where a and b are real numbers and i is an imaginary unit. Complex numbers are an extended idea of one-dimensional number line to two-dimensional complex plane.
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