b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ < 1/\z|. Let C be the closed contour along the boundary of the square with sides 1 = ±3 and y = ±3 (see the screen) Prove that zf(z) dz = 0.
b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ < 1/\z|. Let C be the closed contour along the boundary of the square with sides 1 = ±3 and y = ±3 (see the screen) Prove that zf(z) dz = 0.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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From a calculus course focused on
![b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ <1/\z®. Let C be the
closed contour along the boundary of the square with sides I = ±3 and y = ±3 (see the screen)
Prove that f zf(z) dz = 0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadd5b56d-97e3-4d3c-9aa9-5b563ad77377%2F84ae8201-bd96-477a-98a6-3a579d3c18c6%2Fv58god_processed.png&w=3840&q=75)
Transcribed Image Text:b) A function f is analytic on the domain {|z| > 2}. It also satisfies |f(z)\ <1/\z®. Let C be the
closed contour along the boundary of the square with sides I = ±3 and y = ±3 (see the screen)
Prove that f zf(z) dz = 0.
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