vo B A -10.0 cm
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An electron at point A
in Fig. has a speed v0 of
1.41 * 10^6 m/s. Find (a) the magnitude
and direction of the magnetic
field that will cause the electron to
follow the semicircular path from A
to B, and (b) the time required for
the electron to move from A to B.
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- A long, straight wire lies on a horizontal table in thexy - plane and carries a current of 1.20 µA in the positivex - direction along the x - axis. A proton is traveling in the negativex - direction at speed 2.30 x 104 m/s a distance d abovethe wire (i.e., z = d ). (a) What is the direction of the magneticfield of the wire at the position of the proton? (b) Whatis the direction of the magnetic force acting on the proton?(c) Explain why the direction of the proton’s motion doesn’tchange. (d) Using Newton’s second law, find a symbolicexpression for d in terms of the acceleration of gravity g, theproton mass m, its speed v, charge q, and the current I.(e) Find the numeric answer for the distance d using theresults of part (d).An electron gun in CRT emits electron which moves with the speecd of 3×106 m/s it pasess through a uniform 4.0T magnetic field along the + y-axis . He velocity of each electron is at 50° to the y-axis and lies in the xy-plane.Find the magnitude and direction of force on electron?(a) A velocity selector consists of electric and magnetic fields described by the expressions E = EK and B = Bĵ, with B = 14.0 mT. Find the value of E (in kV/m) such that a 770 eV electron moving in the negative x-direction is undeflected. kv/m (b) What If? For the value of E found in part (a), what would the kinetic energy of a proton have to be (in MeV) for it to move undeflected in the negative x-direction? MeV Need Help? Read It Watch It
- Do it asapRPTwo conducting plates are in parallel and carry net charge of opposite signs with the same magnitude. A particle with negative charge -q is sent into the region between the plates with speed v as shown. What must be the direction of the uniformn magnetic field in the space between the plates such that -q passes in between the plates with no deflections?
- (a) A velocity selector consists of electric and magnetic fields described by the expressions E = Ek and B = B ĵ, with B = 25.0 mT. Find the value of E (in kV/m) such that a 770 eV electron moving in the negative x-direction is undeflected. kv/m (b) What If? For the value of E found in part (a), what would the kinetic energy of a proton have to be (in MeV) for it to move undeflected in the negative x-direction? MeVSuppose we have set up a magnetic field along the +y-direction with a field strength of 0.05T. If a proton is movingat a speed of 2.50×106m/s at an angle of 40o with the direction of a magnetic field what is the acceleration experienced by the proton?(a) A velocity selector consists of electric and magnetic fields described by the expressions E = E K ar undeflected. kv/m and B = Bĵ, with B = 19.0 mT. Find the value of E (in kV/m) such that a 820 eV electron moving in the negative x-direction is (b) What If? For the value of E found in part (a), what would the kinetic energy of a proton have to be (in MeV) for it to move undeflected in the negative x-direction? MeV
- (a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.85 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.20 ✕ 10−5 T? m/s (b) What would the radius (in m) of the path be if the proton had the same speed as the electron? m (c) What would the radius (in m) be if the proton had the same kinetic energy as the electron? mAn electron in a TV CRT moves with a speed of 6.00 X 107 m/s,in a direction perpendicular to the Earth’s field, which has a strength of 5.00 X 10-5 T. If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a correction.)