An electron moves with a speed of 1.99 × 106 m/s along the +x-axis. It enters a region where there is a magnetic field of 1.87 T, directed at an angle of +42° to the +x-axis and lying in the xy-plane. (+z is out of the page, 1 eV = 1.60 × 10-19 C, mel = 9.11 × 10-31 kg) 1. find the magnetic force (vector) on the electron. 2. find the acceleration (vector) of the electron.

Q: An electron moving at 4.00 ✕ 103 m/s in a 1.25 T magnetic field experiences a magnetic force of 1.40…

A: Answer:-  Given  Velocity of electron (V) = 4.00 × 103 m/s  Magnetic field (B) = 1.25 T  Magnetic…

Q: An electron ( mẹ = 9.11×1031 q=1.6×1091 C) moves in a circular kg path perpendicular to a uniform…

A: Here given the electron of mass 9.1 × 10-³¹ kg. The charge is 1.6 × 10-¹⁹ C. It revolves around a…

Q: a) Calculate the speed (vf) that the particle will have when it exits from between the parallel…

A: Given: mass m =1.23*10-26 kgcharge = 5e = 5*1.6*10-19 C = 8*10-19 C  (negative)potential V = 89132.5…

Q: An electron (m=9.1 x 10-31 kg, q=-1.6x10-19 C) traveling at a speed of 2.1 x 108 m/s in the +…

A: Given Mass of electron = m = 9.1 x 10-31 kg charge on electron = q = -1.6x10-19 C speed of electron…

Q: he vector magnetic force acting.

A: Current carried by first long wire I1=28ACurrent carried by first long wire I2=64A

Q: a) What is the direction of E field? b) What magnitude of magnetic field is needed so that the alpha…

A:

Q: A particle with charge q = -0.5 C is moving in the negative y-direction at 3 m/s. The magnetic field…

A:

Q: An electron with an energy of 861 eV is moving in a straight path. What should be the magnitude of…

A: Write the expression for the kinetic energy and substitute the corresponding values to calculate the…

Q: An electron moving at 3.60 ✕ 103 m/s in a 1.45 T magnetic field experiences a magnetic force of 1.40…

A:

Q: An alpha-particle (m = 6.64 × 10−27 kg, q = 3.2 × 10−19 C) travels in a circular path of radius 25…

A: Consider B denotes the magnetic field strength which is given as 1.5 T. Let r denote the radius of…

Q: 9.11X 10 31 kg q=1.6×10 ° C) moves in a circular path perpendicular to a uniform magnetic field with…

A:

Q: What force is felt by a 9.0 nC charge moving at a velocity of 3.0 × 10^4 m/s at an angle of 10° to a…

A: Given,  charge , q = 9.0 nC = 9.0×10-9 C velocity ,v = 3.0 ×104 m/s Magnetic field , B = 8.0×10-4 T…

Q: 5. A uniform magnetic field B =85 az T exists in the region x>0. If an electron enters this field at…

A: Given: The velocity of electron entering the magnetic field = 450ax km/s Magnetic field B =85azT me…

Q: An electron ( me = 9.11x10 31 kg q=1.6x1091 C) moves in a %3D circular path perpendicular to a…

A: The radius of the circular path can be obtained as r=mvqB

Q: A proton (mass = 1.673 × 10-27 kg) moves with an initial velocity (-19.78, -10.73,0) km/s at the…

A: Step 1: To determine the direction of the spiral motion of the proton as observed from the negative…

Q: a magnitude of 9.1 mT. If the speed of the electron is 1.50 \( \times \)107 m/s, determine the…

A: Mass of electron, m=9.11×10-31kg Charge on electron, q=1.6×10-19C Magnetic field strength,…

Q: An electron moving at 4.40 ✕ 103 m/s in a 1.50 T magnetic field experiences a magnetic force of 1.40…

A: Magnitude of charge on electron (q) = 1.6×10-19CVelocity of electron (v) = 4400 msMagnetic force (F)…

Q: An electron (m, = 9.11×10- kg q=1.6× 10: 0) moves in a circular path perpendicular to a uniform…

A: Explanation and solution shown in the picture below ?

Q: Will the particle travel Clockwise or Counterclockwise in the magnetic field? Explain how you…

A: The magnetic field is an invisible space around a magnetic object. A magnetic field is basically…

Q: A proton is launched with a speed of 2.80 x 106 m/s perpendicular to a uniform magnetic field of…

A:

Q: An electron initially at rest is accelerated through a po where a uniform 4.0-mT magnetic field is…

A: Given V=3.75 kV=3.75×103 VB=4.0 mT=4×10-3 Tqe=1.6×10-19 Cme=9.11×10-31 kg

Q: An electron moving at 3.90 ✕ 103 m/s in a 1.20 T magnetic field experiences a magnetic force of 1.40…

A: Velocity of electron (v) = 3.90 ✕ 103 m/s Magnetic field (B) = 1.20 TForce(F) = 1.40 ✕ 10−16 N

Q: B1) An electron enters perpendicularly in a magnetic field (B) of 2.5 T, which is directed into the…

A: Given: The magnetic field is 2.5 T. The velocity of the electron is 2.0×106 m/s. The mass of the…

Q: A beam of electrons moves at 5.0 × 105 ?⁄? through a uniform 4.0 T magnetic field directed along the…

A: Given:Electron moving at speed 5×105 m/sMagnetic field is 4 TAngle is 30°To Find:Force on an…

Q: -27 A proton (mass = 1.673 x 10 kg) moves with an initial velocity (14.32, 3.03, 0) km/s at the…

A: Magnetic Force: For a charged particle with charge q moving in a uniform magnetic field B→ with…

Q: A uniform magnetic field B in +z direction with magnitude 0.9 Tesla is applied. An electron with…

A:

Q: 5. An electron has an instantancous velocity of = (-1.5x104")? + (3.0x10° "ý is moving through the…

A: Given data, Magnitude of charge on an electron/proton = 1.6x10-19 C Mass of a proton = 1.6x10-27 kg…

Q: (L09) A mass spectrometer is used to separate uranium isotopes 235U and 238U. A beam of mixed 235U…

A:

Q: A proton is launched with a speed of 2.90 x 106 m/s perpendicular to a uniform magnetic field of…

A: Given dataThe speed of the proton is given as vp = 2.90 x 106 m/s.The uniform magnetic field is…

Q: At the instant an electron enters a uniform magnetic field of 0.500 T directed along the positive…

A: The centripetal force needed for the circular motion of the electron is supplied by the magnetic…

Q: A proton with a kinetic energy of 2.3 keV follows a circular path in a region where the magnetic…

A: Given : K = 2.3 keV = 2.3 x 103 eV  B = 60 mT = 0.060 T 1 eV = 1.6 x 10-19 J, mp = 1.67 x 10-27 kg

Q: An electron ( me = 9.11×10 q=1.6×10-91 C) moves in a c path perpendicular to a unifo magnetic field…

A: In Magnetic Field  Magnetic Force = Centripetal force  B = 3.2 mT v = 1.50*107 m/s

Q: (a) An electron moves through a uniform electric field E = (2.801 + 5.80J) V/m and a uniform…

A:

Q: An electron ( me = 9.11x 10-31 kg q=1.6x 10-1 C) moves in a circular path perpendicular to a uniform…

A: Given: Formula: Radius of the circular path is given as;

Q: An electron is projected in a perpendicular uniform magnetic field of 3 x 10-3 T. If electron moves…

A: To find-Linear momentum (P)=?Given-Magnetic field (B)=3×10-3 TRadius (r)=4 mm=4×10-3 m

Q: moves circular pati perpendicuiar a magneuic ield of magnitude 0.263 9y of the electron J, ind trne…

A:

Q: A particle of charge q= 1.602x10^-18 C moves vertically with velocity 1.9x10^7 m/s through a…

A: given:charge on particle q = 1.602*10-18 Cvelocity v = 1.9*107m/s  magnetic field strength B =800 Tϕ…

Q: Problem 14: A proton is traveling with a velocity of V = Vxi + vyj, where vx = 93 m/s and vy = 49…

A: Given Data:The velocity of proton is Where,  and The magnetic field is given byWhere,The force on a…

Q: An electron follows a circular path of radius 0.20 m in a uniform magnetic field of 0.3T. Calculate…

A:

Q: An electron (m, 9.11x 10 kg q-16x 10 moves in a circular path perpendicular to a uniform magnetic…

A: B=1.7mT V=1.5 × 107 m/s

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.