(b) 50 mL of 0.005 M Pb2* solution buffered at pH 10 is to be titrated with 0.01 M EDTA solution. Table Q2 shows volume of EDTA added and the corresponding pCA values. The dissociation coefficient, Kr for PbY2 is 1.1 x 1018. The x4 at pH 10 is 0.35. Table Q2: Volume EDTA vs pPb Vol. EDTA (ml). 0.0 pCa a 5.0 10.0 15.0 2.44 b 2.81 25.0 30.0 16.89 50.0 d. (i) Calculate pPb of a, b, c, and d (ii) Define equivalence point.

(b) 50 mL of 0.005 M Pb2* solution buffered at pH 10 is to be titrated with 0.01 M EDTA solution. Table Q2 shows volume of EDTA added and the corresponding pCA values. The dissociation coefficient, Kr for PbY2 is 1.1 x 1018. The x4 at pH 10 is 0.35. Table Q2: Volume EDTA vs pPb Vol. EDTA (ml). 0.0 pCa a 5.0 10.0 15.0 2.44 b 2.81 25.0 30.0 16.89 50.0 d. (i) Calculate pPb of a, b, c, and d (ii) Define equivalence point.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

(b) 50 mL of 0.005 M Pb2* solution buffered at pH 10 is to be titrated with 0.01 M EDTA
solution. Table Q2 shows volume of EDTA added and the corresponding pCA values.
The dissociation coefficient, Kr for PbY2- is 1.1 x 1018. The x4 at pH 10 is 0.35.
Table Q2: Volume EDTA vs pPb
Vol. EDTA (ml)
0.0
pCa
a
5.0
10.0
15.0
25.0
2.44
2.81
30.0
50.0
16.89
(i)
Calculate pPb of a, b, c, and d
(ii)
Define equivalence point.

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