B 3m A (132) (J³) C (331) 2 t/m D $ tust us
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
TRANSCRIBE IN DIGITAL FORMAT
![So
J
EL
3m
3
B
gm
M
AK 5m *4m +
NA
(ES)
Let
Spor AB :
(21) A A
(2E5)
Pdz
sm
HA
MA
T
а что
VA
=
24/m
Least work Principle:
3
P[x] ³²=
EI
4m
NOW,
IMA=0; (2x9) x 4-5
Mx = - P
Р
= MAI VAI VC & VD.
No. of equations of equilibrium = 3 (EV, EH, EM = 0)
Let
MA be
the redundant
Let MA = P
VD be the redundant,
Let Vp = R
2 t/m
VP
3P
EL
SI 3+1+1 = 3
2 5-3
7
SI = 2
Degree of redundancy
EV:0
VA +V₁ +R = 2x9 = 18KN = let
No. of unknown (4 nos)
DMx = -1
ap
Limit 0-10 3
2010 = 1
ΣΗΞΟ;
NA +Ve+ Vo = 2X 9 = 18
HA=0.
Mx Mx
JR
FL
- Vexs - RX 9 - P = 0
dx = 0
815 V₂ -9R - P = 0
5V₁ = (81-9R-P); Vc = (16.2 - 108R -1
t
+ 2
2. VA=
18-R-Vc = 18-R- (162-1.82-0-2P)
> VA * (1.8 +0.8R +0.2P) t
KN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe4cdec65-7837-40d3-b239-1cf845d9f9e2%2F0ae89294-8044-4c5c-8731-fac5b519a155%2F4tcnp5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:So
J
EL
3m
3
B
gm
M
AK 5m *4m +
NA
(ES)
Let
Spor AB :
(21) A A
(2E5)
Pdz
sm
HA
MA
T
а что
VA
=
24/m
Least work Principle:
3
P[x] ³²=
EI
4m
NOW,
IMA=0; (2x9) x 4-5
Mx = - P
Р
= MAI VAI VC & VD.
No. of equations of equilibrium = 3 (EV, EH, EM = 0)
Let
MA be
the redundant
Let MA = P
VD be the redundant,
Let Vp = R
2 t/m
VP
3P
EL
SI 3+1+1 = 3
2 5-3
7
SI = 2
Degree of redundancy
EV:0
VA +V₁ +R = 2x9 = 18KN = let
No. of unknown (4 nos)
DMx = -1
ap
Limit 0-10 3
2010 = 1
ΣΗΞΟ;
NA +Ve+ Vo = 2X 9 = 18
HA=0.
Mx Mx
JR
FL
- Vexs - RX 9 - P = 0
dx = 0
815 V₂ -9R - P = 0
5V₁ = (81-9R-P); Vc = (16.2 - 108R -1
t
+ 2
2. VA=
18-R-Vc = 18-R- (162-1.82-0-2P)
> VA * (1.8 +0.8R +0.2P) t
KN
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