Please answer the following and ignore the previously written answer; (b) a . Reordering the fields of the Dorm struct can reduce its total size and fragmentation.Below, list a new order of fields of the Dorm struct that has the same fields in a different order sothat the total size and fragmentation is minimized; provide the fragmentation and total size. A:New order of fields (names only fine, no need to copy types):Total Struct Size: 28 byres3Internal Fragmentation:External Fragmentation:1 (a) :Consider the Dorm struct definition below. Fill in: the offset of each field fromthe base address of the struct (starting with +0), the total size, and the total amount of internaland external fragmentation..3. Each field with a primitive typeshould be aligned to a multiple of its size, see the reference sheet for sizes. To justify your answers,draw a picture of the positioning of the fields and fragmentation with offsets.struct Dorm { // Total Struct Size (e.g., when used in an array): 32 byteschar *name;// Offset: +0// Offset: +1// Offset: +2// Offset: +3char rating;short numRAS;long capacity;char zipcode [5]; // Offset: +4}; // Internal Fragmentation: Sbyres External Fragmentation: 2bytesPicture:

Let's calculate the offset of each field, the total size, and the total amount of internal and…

(b) 3. Reordering the fields of the Dorm struct can reduce its total size and fragmentation. Below, list a new order of fields of the Dorm struct that has the same fields in a different order so that the total size and fragmentation is minimized; provide the fragmentation and total size. A New order of fields (names only fine, no need to copy types): Total Struct Size: 28 byres 3 Internal Fragmentation: External Fragmentation: 1

(b) 3. Reordering the fields of the Dorm struct can reduce its total size and fragmentation. Below, list a new order of fields of the Dorm struct that has the same fields in a different order so that the total size and fragmentation is minimized; provide the fragmentation and total size. A New order of fields (names only fine, no need to copy types): Total Struct Size: 28 byres 3 Internal Fragmentation: External Fragmentation: 1

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

Please answer the following and ignore the previously written answer;

(b) a . Reordering the fields of the Dorm struct can reduce its total size and fragmentation.
Below, list a new order of fields of the Dorm struct that has the same fields in a different order so
that the total size and fragmentation is minimized; provide the fragmentation and total size. A
:
New order of fields (names only fine, no need to copy types):
Total Struct Size: 28 byres
3
Internal Fragmentation:
External Fragmentation:
1

(a) :
Consider the Dorm struct definition below. Fill in: the offset of each field from
the base address of the struct (starting with +0), the total size, and the total amount of internal
and external fragmentation..
3. Each field with a primitive type
should be aligned to a multiple of its size, see the reference sheet for sizes. To justify your answers,
draw a picture of the positioning of the fields and fragmentation with offsets.
struct Dorm { // Total Struct Size (e.g., when used in an array): 32 bytes
char *name;
// Offset: +0
// Offset: +1
// Offset: +2
// Offset: +3
char rating;
short numRAS;
long capacity;
char zipcode [5]; // Offset: +4
}; // Internal Fragmentation: Sbyres External Fragmentation: 2bytes
Picture:

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