Answered: b) 232U decays to 234Th by a emission.… | bartleby

Related questions

Question

b)
232U decays to 234Th by a emission. The decay t₁ = 4.47 × 10⁹ years.
92
2
i)
Calculate the decay constant, λ.
ii)
If 30 g lump of 238U existed about 4.54 × 10º years ago when the earth
was formed. Find the amount of 238U would be now.
iii)
Determine the number of a particle emitted per second it would currently
emit.

Expert Solution

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Please answer this within 30 mins ! I will upvote !
A certain particle has a half-life of 179. s. What is the decay constant, in s-1?
1) Complete the reaction: 242Am + ? n → 90Sr + 149La + 4n a) n b) 2n c) 3n d) 4n e) 5n 2) Calculate the energy (in MeV) released in the nuclear fission reaction. The atomic masses are 242Am = 242.059549 u, 90Sr = 89.9077387 u, and 149La = 148.934733 u. (Express your answer to six significant figures).
All the nuclides below undergo nuclei decay, write an equation for each process with an explanation. a) complete and explain the alpha decay for the below nuclides. i) AX → ii) 238U →>> 92 b) complete and explain the ß decay for the below nuclides. i) IN → ii) ¹4C → Completed forms to be made available for external moderation. c) complete and explain the B* decay for the below nuclides. i) 4X → ii) ¹3/N →
Consider the fission reaction 141 n + U -> 235, 92U syXe + 92 38Sr +3n The masses of the components are 235 235.04393 세 xe| 140.여 2678 92 5 91.911 038 n 1.00 866 U Find the energy released in MeV Use the editor to format your answer
b) What type of decay is happening in the equation below? State two of the conservation laws that apply and explain how they are satisfied 238 92 U 234 Th + 4 a 90 2 c) Use the graph below to calculate the half-life of Protactinium 234, explain how you got your answer. Half Life of Protactinium 234 50 40 30 20 10 222222° 80 70 60 Activity (Bq) 0 20 20 40 40 60 80 100 120 140 160 Time (seconds)