AX1 AX2 -4-2 3 1 СЕВЕ -2-7 6 2 1 2 6 -1 -4 -2 3 -2 -7 6 1 2-6 -4 -2 3 -2-7 6 1 2 6 Ax3 = 0 3 100 JT 000 I 1 IT L 43- 12*2 0 3 -11 -3 1 2 d1x1 A3*3
AX1 AX2 -4-2 3 1 СЕВЕ -2-7 6 2 1 2 6 -1 -4 -2 3 -2 -7 6 1 2-6 -4 -2 3 -2-7 6 1 2 6 Ax3 = 0 3 100 JT 000 I 1 IT L 43- 12*2 0 3 -11 -3 1 2 d1x1 A3*3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Verify that ; is an eigenvalue of A and that x; is a corresponding eigenvector.
-4 -2
3
A =
-2 -7
6
A₁ = -11, x₁ = (1, 2, -1)
2₂= = -3, x2 = (-2, 10)
= -3, x3 = (3, 0, 1)
1 2 -6
13
= -11
= 2₁x₁
12x2
Ax1 =
Ax2 =
Ax3
=
-4 -2 3
-2 -7 6
1 2 6
-4 -2 3
-2 -7
w
1
2
-1
I
-2
=
1 =
0
6
1 2 -6
-4 -2
3 3
-2 -7 6 0 =
1 2 -6 1
00
↓↑
000
↓↑
000
11
↓ T
1
2
-1
-2
[1]
0
3
-8 -
-3
=
1
=
13x3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd496c25d-6621-40aa-914c-10320ef32b36%2F4310e817-e7b2-4d4d-9726-6d195c31cf45%2Fvqqzslq_processed.png&w=3840&q=75)
Transcribed Image Text:Verify that ; is an eigenvalue of A and that x; is a corresponding eigenvector.
-4 -2
3
A =
-2 -7
6
A₁ = -11, x₁ = (1, 2, -1)
2₂= = -3, x2 = (-2, 10)
= -3, x3 = (3, 0, 1)
1 2 -6
13
= -11
= 2₁x₁
12x2
Ax1 =
Ax2 =
Ax3
=
-4 -2 3
-2 -7 6
1 2 6
-4 -2 3
-2 -7
w
1
2
-1
I
-2
=
1 =
0
6
1 2 -6
-4 -2
3 3
-2 -7 6 0 =
1 2 -6 1
00
↓↑
000
↓↑
000
11
↓ T
1
2
-1
-2
[1]
0
3
-8 -
-3
=
1
=
13x3
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