Ax = b has exactly one solution for every n*1 matrix b, then det(A) # 0

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Let A be an n*n square matrix.

Prove :

If Ax = b has exactly one solution for every n*1 matrix b, then det(A) # 0

Can you kindly explain how we can prove that, without using the definition of det(A) : det(A) = adj(A) / A_inverse

 

Thank you!

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