Automobile repair costs continue to rise with the average cost now at $367 per repair (U.S. News & World Report website). Assume that the cost for an automobile repair is normally distributed with a standard deviation of $88. Answer the following questions about the cost of automobile repairs. d. If the cost for your car repair is in the lower 5% of automobile repair charges, what is your cost (to two decimals)?

Automobile repair costs continue to rise with the average cost now at $367 per repair (U.S. News & World Report website). Assume that the cost for an automobile repair is normally distributed with a standard deviation of $88. Answer the following questions about the cost of automobile repairs. d. If the cost for your car repair is in the lower 5% of automobile repair charges, what is your cost (to two decimals)?

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Solve the problem. A dot plot of the speeds of a sample of 50 cars passing a policeman with a radar gun is shown. below. L 45 47 49 07 0.50 What proportion of the motorists were driving above the posted speed limit of 55 miles per hour? 0.64 51 0.14 I 53 55 57 59 61 63 65 67 69
The amount of time adults spend watching television is closely monitored by firms because this helps to determine advertising pricing for commercials. Complete parts (a) through (d). (a) Do you think the variable "weekly time spent watching television" would be normally distributed? If not, what shape would you expect the variable to have? A. The variable "weekly time spent watching television" is likely skewed left, not normally distributed. B. The variable "weekly time spent watching television" is likely normally distributed. C. The variable "weekly time spent watching television" is likely uniform, not normally distributed. D. The variable "weekly time spent watching television" is likely symmetric, but not normally distributed. E. The variable "weekly time spent watching television" is likely skewed right, not normally distributed.
Solve this question for me please.
Use a calculator or computer software to generate a normal quantile plot for the data in the accompanying table. Then determine whether the data come from a normally distributed population. Click the icon to view the data set. Generate a normal quantile plot for the data. Choose the correct graph below. OA. 3.00 2.00- 1.00- 0.00- -1.00- -2.00- -3.00- 0 100 200 300 400 500 X Value Data table Space Flight Durations (hours) 0 350 100 400 300 200 50 150 200 OB. 3.00- 2.00- Print 1.00- 0.00- -1.00- -2.00- -3.00+ 0 BEELD 100 200 300 400 500 X Value 300 300 200 100 450 200 50 0 0 400 100 450 G Determine whether the data come from a normally distributed population. Choose the correct answer below. OA. The distribution is not normal. The points are not reasonably close to a straight line. OB. The distribution is normal. The points show a systematic pattern that is not a straight-line pattern. OC. The distribution is normal. The points are not reasonably close to a straight line and do not show…
Sofia wants to determine the average household expenditure on lawn care products per year. She believes that the standard deviation is 19.2. She wants to be 95% confident. How many people does she need to ask for a margin of error of $2.50? Round the answer as you should for this type of problem.(Don't worry if Canvas adds extra zeros after the decimal.)
Give me detailed and accurate solution
Solve d please
The amount of time adults spend watching television is closely monitored by firms because this helps to determine advertising pricing for commercials. Complete parts (a) through (d). C (a) Do you think the variable "weekly time spent watching television" would be normally distributed? If not, what shape would you expect the variable to have? A. The variable "weekly time spent watching television" is likely skewed right, not normally distributed. OB. The variable "weekly time spent watching television" is likely symmetric, but not normally distributed. O C. The variable "weekly time spent watching television" is likely skewed left, not normally distributed. O D. The variable "weekly time spent watching television" is likely normally distributed. O E. The variable "weekly time spent watching television" likely uniform, not normally distributed. (b) According to a certain survey, adults spend 2.45 hours per day watching television on a weekday. Assume that the standard deviation for "time…
The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the SD of the measurements is 20 mm. The histogram looks reasonably like a normal curv Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct. A 19.1% B 30.9% C 38.2% D 69.1% E 68.27% A The percentage of people with blood pressure between 130 and 150 mm. B The percentage of people with blood pressure between 140 and 150 mm. D The percentage of people with blood pressure over 150 mm.
Explain why it makes sense that the standard deviation of X is in the denominator of the formula calculating the standard error of the slope.
Psychology students in the Izmir University of Economics completed the Dental Anxiety Scale questionnaire in 2020. In this study, scores on the scale range from 0 (no anxiety) to 20 (extreme anxiety). The mean score was 14 and the standard deviation was 3.5. Assume that the distribution of all scores on the Dental Aroxiety Scale is normal with u= 14 and g=35. Complete parts a through c A Click here to view a table of areas under the standardized normal curve O Table of Normal Curve Areas a. Suppose you score a 18 on the Dental Anxiety Scale. Find the z-value for this score. z= (Round to the nearest hundredth as needed ) b. Find the probability that someone scores between 13 and 18 on the Dental Anxiety Scale P(13sxs 18) =D (Round to four decimal places as needed) c. Find the probability that someone scores above 17 on the Dental Anxiety Scale P(x> 17)=(Round to four decimal places as needed.) Enter your answer in each of the answer boxes. |8 目國 100 |8 案 |8 業可 0 | 会效到商同我目 |
d. Estimate the blood pressure of the student if his stress test score is 80, 60, and 85.