Atomic nuclei are made of protons and neutrons. This shows that there must be another kind of interaction in addition to gravitational and electric forces. Explain.
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Atomic nuclei are made of protons and neutrons. This shows that there must be another kind of interaction in addition to gravitational and electric forces. Explain.
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- 3. Determine the direction of the force on a proton if it has a velocity in the +y direction and is moving through a B-field that is oriented along the -z direction? A. No force acts B. -Y C. +Z D. -XAfter running PhET simulations on electrostatic forces with a previous knowledge on universal law of gravitation, you may conclude 1.Gravitational attraction (FG) between two protons can't be compared with the electrostatic repulsion (Fq) as one is based on inertial property and the other is based on electrical properties 2. Gravitational attraction (FG) between two protons and the electrostatic repulsion (Fq) may be considered as an action-reaction pair. 3. Relative to the gravitational attraction (FG) between two protons, the electrostatic repulsion (Fq) is much stronger 4. Relative to the gravitational attraction (FG) between two protons, the electrostatic repulsion (Fq) is much weakerIn the figure below, q1 = 1.50×10^−7 C and q2 = 3.50×10^−7 C 1)What is the x component of the force F⃗ acting on an proton at that position? (Express your answer to three significant figures.) 2)What is the y component of the force F⃗ acting on an proton at that position? (Express your answer to three significant figures.)
- You rub a small glass ball with a piece of silk, giving the ball a charge of 3.0 x 10C North B. West Determine the magnitude of the force due to Earth's magnetic field if you throw the ball with a velocity of 6.0 m/s toward geographic west (Hint: 1T=1 kg/C-s) A 9.0 x 10-12 N B. 10x 104 N O C 25x 1013 N D. 11 x 1011 NTHIS IS THE PREVIOUS QUESTION IT IS REFERRING TOO!! Your object has a mass of 35.6 kg. You separate an equal amount of protons and electrons into two boxes. You place the boxes at a distance of 80 m apart from one another. How much force attracts the two boxes to one another? Similar situation to the previous question, but now the object s mass is 60.0 kg and you initially put the boxes of protons and electrons 24 m apart. Now you want to take the two boxes and move them farther apart, to a new distance of 45 m apart. How much work (that is, energy) would you have to expend to pull the boxes that much farther apart, fighting against the electrostatic attraction between them? 1.44E+27 J 2.88E+27 J 5.76E+27 J 7.20E+26 J6. Two identical charged particles of mass 70 grams are at the ends of strings that are the same length l = 10 cm attached to the ceiling. The charged particles repel, as shown in the sketch below: The angle between the strings is o = 20°. Use force analysis to develop equations that describe the balance of forces along both the horizontal and the vertical directions. If we let the symbols 'FG' and 'FE' represent gravitational and electric force magnitude, type the symbol in the first answer box that corresponds to the force that balances out the tension along the - direction. In the second answer box type in the symbol for the force that balances out the tension along the , direction. Ft.x L Fr.y =[ Not yet correct, tries 6/18 Submit All Answers Hint: Try to work purely symbolically without substituting any numbers. Draw a free body diagram that shows the forces acting on one of the charged particles. There should be three forces: gravitational, electric, and tension from the string.…
- 3) Please answer this one! Your object has a mass of 43.8 kg. You separate the protons and electrons into two boxes. You place the boxes at a distance of 26 m apart from one another. How much force attracts the two boxes to one another? 5.85E+25 N 1.17E+26 N 2.34E+26 N 2.93E+25 NWhat charge is required to produce a repulsive force of 10 microNewtons on a charge q= 4.5 nanoC that is 5.0 m away?9)
- Please answer all of the questions in the picture and SHOW ALL OF YOUR WORK IN PICTURES PLEASE, DO NOT TYPE IT! THANK YOU FOR YOUR HELP.Explain stepsQuestions 5-6 refer to the figure below. 0.25 m 0.1 m 91 в 0.1 т A 92 5. In the Figure q = -6.25 × 10–9 C and 2 = -12.5 × 10-9 C are separated by a distance of 0.25 m. Calculate the E-field due to q1 and q2 at point A, which is a distance of 0.1 m to the left of q1. A. – 384.7 ât N/C В. - 6536.1 î N/C C. 384.7 ât N/C D. 6536.1 â& N/C 6. In the Figure q1 = -6.25 × 10–9 C and 2 = -12.5 × 10-9 C are separated by a distance of 0.25 m. Calculate the E-field due to q and q2 at point B, which is a distance of 0.1 m to the left of q2. A. – 529.6 â& N/C B. – 8740.3 ât N/C C. 529.6 £ N/C D. 8740.3 ⣠N/C