AtomHO2Reactant side622Product side212N₂ Hq + H₂O₂ →> N₂ + H₂OOn thereactant sicheH206there are le H and on productSide only 2 so to balance the # mulitply H₂0 by4 and H₂0₂ by 220N₂ H 4 + 2H₂O₂ →> N₂ + 4H ₂0Now balancing of hydrogen has also balancedoxygen and nitrogen was already balanced1 N ₂ H ₂ + Z H ₂ O ₂ →> 1 N₂ + 4H₂O22

According to the law of conservation of mass, we must balance each chemical equation.To balance it,…

Atom H N 6 2 2 Reactant side Product side 2 N₂ H4 + H₂O₂ → N₂ + H ₂ O On the reactant side there are le H and on product Side only 2 so to balance the # mulitply H₂0 by 4 and H₂0₂ by 2 N₂ H4 + 2H₂O₂ →→> N₂ + 4H ₂0 Now balancing of hydrogen has also balanced oxygen and nitrogen was already balanced IN₂ H₂ + ZH₂O₂ →→ 1/₂ + 4H₂₂0₂

Atom H N 6 2 2 Reactant side Product side 2 N₂ H4 + H₂O₂ → N₂ + H ₂ O On the reactant side there are le H and on product Side only 2 so to balance the # mulitply H₂0 by 4 and H₂0₂ by 2 N₂ H4 + 2H₂O₂ →→> N₂ + 4H ₂0 Now balancing of hydrogen has also balanced oxygen and nitrogen was already balanced IN₂ H₂ + ZH₂O₂ →→ 1/₂ + 4H₂₂0₂

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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