1 atm = 760 mm HgR = 0.0821 L atm/ mol KK = °C + 273PV = nRTMolar volume @ STP, 1 mole = 22.4L of ideal gas1.The inflation of an automobile airbag involves several chemical reactions thatproduce nitrogen gas. One important reaction is listed below10NA(s) + 2KNO3(s) –> K¿0(s) + 5N22O(s) + N2(g)If a side airbag contains 71.3 g Na and 75.9 g KNO3, to what pressure, in mm Hg, woulda 5.30 L airbag inflate (due to the production of nitrogen gas) if the reaction occurs at atemperature of 72.0°C.

The question is based on the concept of Reaction Stoichiometry. We have to identify the limiting…

atm = 760 mm Hg = 0.0821 L atm/ mol K %3D = °C + 273 V = nRT folar volume @ STP, 1 mole = 22.4L of ideal gas The inflation of an automobile airbag involves several chemical reactions luce nitrogen gas. One important reaction is listed below 10Na(s) + 2KNO3(s) –> K¿O(s) + 5Na2O(s) + N2(g) side airbag contains 71.3 g Na and 75.9 g KNO3, to what pressure, in mm Hg, 30 L airbag inflate (due to the production of nitrogen gas) if the reaction occur perature of 72.0°C.

atm = 760 mm Hg = 0.0821 L atm/ mol K %3D = °C + 273 V = nRT folar volume @ STP, 1 mole = 22.4L of ideal gas The inflation of an automobile airbag involves several chemical reactions luce nitrogen gas. One important reaction is listed below 10Na(s) + 2KNO3(s) –> K¿O(s) + 5Na2O(s) + N2(g) side airbag contains 71.3 g Na and 75.9 g KNO3, to what pressure, in mm Hg, 30 L airbag inflate (due to the production of nitrogen gas) if the reaction occur perature of 72.0°C.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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