b What is the initial rate of the reaction in Experiment 4? Initial rate= mol/(L.s)

Chemistry
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Chapter1: Chemical Foundations
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2NO(g) + O₂(g) → NO2(g)
Conc. NO, mol/L
Exp. 1 4.3 x 10-2
Exp. 2 4.3 x 10-2
Exp. 3 8.6 x 10-²
Exp. 4 0.63
Conc. 02, mol/L
2.4 x 10-²
4.8 x 10-2
9.6 x 10-²
5.4 x 10-³
Initial Rate
8.0 x 10³ mol/(L.s)
1.6 x 102 mol/(L.s)
0.13 mol/(L.s)
?
a What is the experimental rate law for the reaction above?
(Use k for the rate constant.)
Rate law = K[NO]²[0₂]✔
Co-
The reaction is first order in O₂ because the rate doubled with a do
second order in NO because the rate increased by a factor of 8 wh
Rate = k[NO] ² [0₂]
b What is the initial rate of the reaction in Experiment 4?
Initial rate=
mol/(L.s)
Transcribed Image Text:2NO(g) + O₂(g) → NO2(g) Conc. NO, mol/L Exp. 1 4.3 x 10-2 Exp. 2 4.3 x 10-2 Exp. 3 8.6 x 10-² Exp. 4 0.63 Conc. 02, mol/L 2.4 x 10-² 4.8 x 10-2 9.6 x 10-² 5.4 x 10-³ Initial Rate 8.0 x 10³ mol/(L.s) 1.6 x 102 mol/(L.s) 0.13 mol/(L.s) ? a What is the experimental rate law for the reaction above? (Use k for the rate constant.) Rate law = K[NO]²[0₂]✔ Co- The reaction is first order in O₂ because the rate doubled with a do second order in NO because the rate increased by a factor of 8 wh Rate = k[NO] ² [0₂] b What is the initial rate of the reaction in Experiment 4? Initial rate= mol/(L.s)
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