Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
Problem 120QRT
Related questions
Question
![2NO(g) + O₂(g) → NO2(g)
Conc. NO, mol/L
Exp. 1 4.3 x 10-2
Exp. 2 4.3 x 10-2
Exp. 3 8.6 x 10-²
Exp. 4 0.63
Conc. 02, mol/L
2.4 x 10-²
4.8 x 10-2
9.6 x 10-²
5.4 x 10-³
Initial Rate
8.0 x 10³ mol/(L.s)
1.6 x 102 mol/(L.s)
0.13 mol/(L.s)
?
a What is the experimental rate law for the reaction above?
(Use k for the rate constant.)
Rate law = K[NO]²[0₂]✔
Co-
The reaction is first order in O₂ because the rate doubled with a do
second order in NO because the rate increased by a factor of 8 wh
Rate = k[NO] ² [0₂]
b What is the initial rate of the reaction in Experiment 4?
Initial rate=
mol/(L.s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2d324e2-7a67-4e3d-bb22-9ad23fbeb72b%2Fedb1df5c-df81-45d1-a09e-b4319b226b3d%2F0nlgteo_processed.png&w=3840&q=75)
Transcribed Image Text:2NO(g) + O₂(g) → NO2(g)
Conc. NO, mol/L
Exp. 1 4.3 x 10-2
Exp. 2 4.3 x 10-2
Exp. 3 8.6 x 10-²
Exp. 4 0.63
Conc. 02, mol/L
2.4 x 10-²
4.8 x 10-2
9.6 x 10-²
5.4 x 10-³
Initial Rate
8.0 x 10³ mol/(L.s)
1.6 x 102 mol/(L.s)
0.13 mol/(L.s)
?
a What is the experimental rate law for the reaction above?
(Use k for the rate constant.)
Rate law = K[NO]²[0₂]✔
Co-
The reaction is first order in O₂ because the rate doubled with a do
second order in NO because the rate increased by a factor of 8 wh
Rate = k[NO] ² [0₂]
b What is the initial rate of the reaction in Experiment 4?
Initial rate=
mol/(L.s)
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