a)The highest order distributed load upon this beam is x to the power of _____. b)The uniform intensity has a magnitude of _____ N/m. c) ASIDE: The commonly used variable used to represent intensity is the letter _____.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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5.12

a)The highest order distributed load upon this beam is x to the power of _____.

b)The uniform intensity has a magnitude of _____ N/m.

c)

ASIDE:

The commonly used variable used to represent intensity is the letter _____.

 

 options:

 

w

 

y

 

r

 

c

 

R

 

m

 

b

 

x

 

X

 

d

 

a

 

A

 

K

 

M

 

Y

 

W

 

k

 

B

d)The resultant force of the distribution has a magnitude of _____ N.

e)

The centroid of the distribution is located at x=_____m as measured from A.

 

NOTE:

Submit 3 Sig Fig.

f)

The moment about A induced by the distribution has a magnitude of _____ N-m.

 

NOTE:

Submit 3 Sig Fig.

g)

The sense of the moment about A induced by the distribution is _____.

 

Question 7 options:

 

+x

 

-x

 

+y

 

-y

 

+z

 

-z

h)

The reaction moment induced by the distribution has a magnitude of _____ N-m.

 

NOTE:

Submit 3 Sig Fig.

i)

The sense of the reaction moment induced by the distribution is _____.

 

Question 9 options:

 

+x

 

-x

 

+y

 

-y

 

+z

 

-z

SAMPLE PROBLEM 5/12
w(x)
W = Wo + kx?
2024
N/m
1000 N/m
Determine the reaction at the support A of the loaded cantilever beam.
8 m
1000
||
Solution. The constants in the load distribution are found to be wo
A
1 N/m and k = 2 N/m4. The load R is then
%3D
8
Helpful Hints
8
(1000 + 2x³) dx =
1000x +
2
= 10 050 N
R =
w dx =
1 Use caution with the units of the
constants wn and k.
The x-coordinate of the centroid of the area is found by
2 The student should recognize that
the calculation of R and its location x
xw dx
1
x =
x(1000 + 2x3) dx
%3D
is simply an application of centroids
as treated in Art. 5/3.
R
10 050
1
(500x² +)
Fr5 = 4.49 m
10 050
10 050 N
From the free-body diagram of the beam, we have
4.49 m
A
MA
y
MA - (10 050)(4.49) = 0
bios
= 45 100 N m
[ΣΜΑ-0]
Ans.
A,
beon
L-- X
MA =
[EF, = 0]
A,
10 050 N
Ans.
Note that A, = 0 by inspection.
Transcribed Image Text:SAMPLE PROBLEM 5/12 w(x) W = Wo + kx? 2024 N/m 1000 N/m Determine the reaction at the support A of the loaded cantilever beam. 8 m 1000 || Solution. The constants in the load distribution are found to be wo A 1 N/m and k = 2 N/m4. The load R is then %3D 8 Helpful Hints 8 (1000 + 2x³) dx = 1000x + 2 = 10 050 N R = w dx = 1 Use caution with the units of the constants wn and k. The x-coordinate of the centroid of the area is found by 2 The student should recognize that the calculation of R and its location x xw dx 1 x = x(1000 + 2x3) dx %3D is simply an application of centroids as treated in Art. 5/3. R 10 050 1 (500x² +) Fr5 = 4.49 m 10 050 10 050 N From the free-body diagram of the beam, we have 4.49 m A MA y MA - (10 050)(4.49) = 0 bios = 45 100 N m [ΣΜΑ-0] Ans. A, beon L-- X MA = [EF, = 0] A, 10 050 N Ans. Note that A, = 0 by inspection.
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