At time t = 14 s, the velocity of a particle moving in the x-y plane is v=0.06i+2.45j m/s. By time t = 14.06 s, its velocity has become -0.04i +2.31j m/s. Determine the magnitude any of its average acceleration during this interval and the angle 9 made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: aav= 0= m/s²

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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At time t = 14 s, the velocity of a particle moving in the x-y plane is v = 0.06i + 2.45j m/s. By time t = 14.06 s, its velocity has become
-0.04i + 2.31j m/s. Determine the magnitude day of its average acceleration during this interval and the angle 8 made by the average
acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis.
Answers:
aav =
0=
i
i
m/s²
Transcribed Image Text:At time t = 14 s, the velocity of a particle moving in the x-y plane is v = 0.06i + 2.45j m/s. By time t = 14.06 s, its velocity has become -0.04i + 2.31j m/s. Determine the magnitude day of its average acceleration during this interval and the angle 8 made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: aav = 0= i i m/s²
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