At time t = 12 s, the velocity of a particle moving in the x-y plane is v = 0.11i +2.72j m/s. By time t = 12.05 s, its velocity has become -0.03i + 2.61j m/s. Determine the magnitude day of its average acceleration during this interval and the angle e made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav= 0= i i m/s² O W

At time t = 12 s, the velocity of a particle moving in the x-y plane is v = 0.11i +2.72j m/s. By time t = 12.05 s, its velocity has become -0.03i + 2.61j m/s. Determine the magnitude day of its average acceleration during this interval and the angle e made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav= 0= i i m/s² O W

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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