At time t = 0 an elevator starts moving upward from the ground at a constant speed vo. At a later time t = T₁ = 4.63s a marble is "let go" through the floor. In other words, imagine a marble resting on the floor of the elevator and a trap door of sorts opening up from under the marble. See the image below. The marble then hits the ground at a still later time t = T₂ = 9.34 s. What is the maximum height (above the ground) that the marble reaches in this process? elevator trapdoor opening Image size: S M L Max
At time t = 0 an elevator starts moving upward from the ground at a constant speed vo. At a later time t = T₁ = 4.63s a marble is "let go" through the floor. In other words, imagine a marble resting on the floor of the elevator and a trap door of sorts opening up from under the marble. See the image below. The marble then hits the ground at a still later time t = T₂ = 9.34 s. What is the maximum height (above the ground) that the marble reaches in this process? elevator trapdoor opening Image size: S M L Max
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:At time t = 0 an elevator starts moving upward from the ground at a constant speed vo. At a later time t = T₁ = 4.63s a marble is "let go" through the floor.
In other words, imagine a marble resting on the floor of the elevator and a trap door of sorts opening up from under the marble. See the image below. The
marble then hits the ground at a still later time t = T₂ = 9.34 s.
What is the maximum height (above the ground) that the marble reaches in this process?
trapdoor opening
Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8
Image size: S M L Max
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