At time t = 0, an electron with kinetic energy 9.2 keV moves through x O in the positive direction of an x axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 69.9 uT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinate x 18 cm? (a) Number i Units (b) Number Units

At time t = 0, an electron with kinetic energy 9.2 keV moves through x O in the positive direction of an x axis that is parallel to the horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 69.9 uT. (a) What is the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's distance from the x axis in centimeters when the electron reaches coordinate x 18 cm? (a) Number i Units (b) Number Units

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter30: Magnetic Fields And Forces

Section: Chapter Questions

Problem 43PQ

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At time t = 0, an electron with kinetic energy 9.2 keV moves through x = 0 in the positive direction of an x axis that is parallel to the
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horizontal component of Earth's magnetic field. The field's vertical component is downward and has magnitude 69.9 uT. (a) What is
the magnitude of the electron's acceleration in meters per second squared, due to the magnetic field? (b) What is the electron's
distance from the x axis in centimeters when the electron reaches coordinatex = 18 cm?
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(a) Number
i
Units
(b) Number
i
Units
>

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