at The magnetic flux through the loop shown in the accompanying figure varies with time according to Φm = Poe sin(wt), where Po = 4 x 10-³ T m², a = 5 s-¹, and w = 120 rad/s. What are the direction and magnitude of the current through the 5-0 resistor at (a) t = 0; (b) t = 2.17 × 10−² s, and (c) t = 3.00 s? * 5.0 Ω tm
at The magnetic flux through the loop shown in the accompanying figure varies with time according to Φm = Poe sin(wt), where Po = 4 x 10-³ T m², a = 5 s-¹, and w = 120 rad/s. What are the direction and magnitude of the current through the 5-0 resistor at (a) t = 0; (b) t = 2.17 × 10−² s, and (c) t = 3.00 s? * 5.0 Ω tm
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Transcribed Image Text:- at
&m
=
- 2
The magnetic flux through the loop shown in the accompanying figure varies with time according to
Poe sin(wt), where Do = 4 × 10-³ T · m², a = 5 s-¹, and w = 120 rad/s. What are the
direction and magnitude of the current through the 5-0 resistor at (a) t = 0; (b) t = 2.17 × 10¯ s, and (c)
t = 3.00 s?
' 5.0 Ω
Hints
mA at t = 0.
a. Current
mA at t
b. Current
mA at t
c. Current
●tm
B
Select an answer
Select an answer
Select an answer
with
with
with
- 2
= = 2.17 × 10- S.
= 3.00 s.
-
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