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At the instant shown the boomerang has an angular velocity w = 5 rad/s, and its mass center G has a velocity VG = 6 in./s. (Figure 1) Figure 1.5 in. 45 5 in 1 of 1 Part A Determine the x and y components of the velocity of point B at this instant. Express your answers using three significant figures separated by a comma. (VB)z. (UB)y= Submit Provide Feedback [VE| ΑΣΦ | Η Request Answer vec ? in. /s

At the instant shown the boomerang has an angular velocity w = 5 rad/s, and its mass center G has a velocity VG = 6 in./s. (Figure 1) Figure 1.5 in. 45 5 in 1 of 1 Part A Determine the x and y components of the velocity of point B at this instant. Express your answers using three significant figures separated by a comma. (VB)z. (UB)y= Submit Provide Feedback [VE| ΑΣΦ | Η Request Answer vec ? in. /s

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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At the instant shown the boomerang has an angular velocity ωωomega = 5 rad/srad/s , and its mass center GG has a velocity vGvGv_G = 6 in./sin./s .

Determine the xx and yy components of the velocity of point BB at this instant.

### Educational Content on Boomerang Motion #### Problem Statement At the instant shown, the boomerang has an angular velocity \(\omega = 5 \, \text{rad/s}\), and its mass center \(G\) has a velocity \(v_G = 6 \, \text{in./s}\). #### Task **Part A**: Determine the \(x\) and \(y\) components of the velocity of point \(B\) at this instant. Express your answers using three significant figures separated by a comma. #### Solution Input You are required to compute: \[ (v_B)_x, (v_B)_y = \quad \text{in./s} \] *Enter the values and submit your answer.* #### Figure Explanation The diagram shows a boomerang with the following details: - **Mass Center (G)**: Positioned such that \(v_G = 6 \, \text{in./s}\) is directed at a \(30^\circ\) angle to the horizontal axis. - **Dimensions**: - Distance between mass center \(G\) and point \(B\) is \(1.5 \, \text{in.}\). - The angle between segment \(G\) to \(B\) and the horizontal is \(45^\circ\). - The full length from point \(A\) to point \(B\) is \(5 \, \text{in.}\). - **Angular Direction**: The given angular velocity causes rotation with a noted direction at point \(B\) highlighted by an arc labeled \(60^\circ\). Use these details to calculate the velocity components at point \(B\).
Transcribed Image Text:### Educational Content on Boomerang Motion #### Problem Statement At the instant shown, the boomerang has an angular velocity \(\omega = 5 \, \text{rad/s}\), and its mass center \(G\) has a velocity \(v_G = 6 \, \text{in./s}\). #### Task **Part A**: Determine the \(x\) and \(y\) components of the velocity of point \(B\) at this instant. Express your answers using three significant figures separated by a comma. #### Solution Input You are required to compute: \[ (v_B)_x, (v_B)_y = \quad \text{in./s} \] *Enter the values and submit your answer.* #### Figure Explanation The diagram shows a boomerang with the following details: - **Mass Center (G)**: Positioned such that \(v_G = 6 \, \text{in./s}\) is directed at a \(30^\circ\) angle to the horizontal axis. - **Dimensions**: - Distance between mass center \(G\) and point \(B\) is \(1.5 \, \text{in.}\). - The angle between segment \(G\) to \(B\) and the horizontal is \(45^\circ\). - The full length from point \(A\) to point \(B\) is \(5 \, \text{in.}\). - **Angular Direction**: The given angular velocity causes rotation with a noted direction at point \(B\) highlighted by an arc labeled \(60^\circ\). Use these details to calculate the velocity components at point \(B\).
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