At the end of the school year a high school chemistry teacher asks one of his/her students to stay after school and help clean the storage room. While cleaning, the student finds a rectangular block of metal that is not labeled and is therefore unknown. The teacher challenges the student to identify the metal using density. The student measures each side of the block (using a centimeter ruler) and determines the length is 3.00 cm, height is 5.00 cm, and width is 5.00 cm. The student then takes the mass of the block using a centigram balance and reports the mass as 337.50 g. The student then researched the density of different materials. Metal Density Tantalum 16.67 g/cm Tantalum 16.667 g/cm Titanium 4.50 g/cm Titanium 5 g/cm What is the identity of the unknown metals and gives the most appropriate answer given the data as measured by the student? O A The unknown metal is tantalum because the density of tantalum is 16.67g/cm^3, The number reported by the student uses the proper number of significant figures based on the precision of the scientific equipment. B. The unknown metal is tantalum because the density of tantalum is 16.667 g/cm^3. The number reported by the student uses the proper number of significant figures

At the end of the school year a high school chemistry teacher asks one of his/her students to stay after school and help clean the storage room. While cleaning, the student finds a rectangular block of metal that is not labeled and is therefore unknown. The teacher challenges the student to identify the metal using density. The student measures each side of the block (using a centimeter ruler) and determines the length is 3.00 cm, height is 5.00 cm, and width is 5.00 cm. The student then takes the mass of the block using a centigram balance and reports the mass as 337.50 g. The student then researched the density of different materials. Metal Density Tantalum 16.67 g/cm Tantalum 16.667 g/cm Titanium 4.50 g/cm Titanium 5 g/cm What is the identity of the unknown metals and gives the most appropriate answer given the data as measured by the student? O A The unknown metal is tantalum because the density of tantalum is 16.67g/cm^3, The number reported by the student uses the proper number of significant figures based on the precision of the scientific equipment. B. The unknown metal is tantalum because the density of tantalum is 16.667 g/cm^3. The number reported by the student uses the proper number of significant figures

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

The chemist measures the volume of the unknown liquid as 0.615 L and the mass of the unknown liquid as 385. g. Calculate the density of the liquid. Be sure your answer has the correct number of significant digits. Is it possible to identify the liquid? If it is possible to identify the liquid, do so.
A sample containing 34.92 g of metal pellets is placed into a graduated cylinder initially containing 13.0 mL of water, causing the water level in the cylinder to rise to 21.6 mL. Calculate the density of the metal.
Please send me the question in 20 minutes it's very urgent plz
Please don't provide handwriting solution
from the chart to see what the normal person can see from 100 feet away. In Britain, eye doctors use 37) In the United States, vision is tested by having the person attempt to read letters at a certain distance person's vision who scored 20/100 vision on the United States scale(1 inch32.54 cm)? a sìmilar test, however, the distance is measured in meters. For example, poor vision is 20/100, meaning that this person must be 20 feet away measured in feet. person's vision who scored 20/100 vision on the Und tates scale(1 inch32.54 cm)? How would a British doctor record a a) 5.3/28 b) 6.1/31 c) 7.4/38 ) 8.5/42
2. A procedure calls for 1.5 lb of hexane, a liquid with a density of 0.6594 g/mL. Rather than weigh the sample, a chemist chooses to measure the liquid in a graduated cylinder. What volume, in mL, of the liquid should be used? density = 0.6694g/mL 4539 2260 = 11b 680.4 = 1.51b A story calls for the hero sprinting off with a gold brick and the author wants to determine if that o size as a typical brick, 1020 cm³, then calculate the mass ld include this in the
An electric current transports 69.0 C of charge in 57.0 seconds. Calculate the size of the electric current. Be sure your answer has the correct unit symbol and 3 significant digits. 0 x10 0.0 3 Ś
The density of iron is 7.9 g/mL. a) What is the mass of a sample of iron that has a volume of 7.1 mL? b) what is the volume of a sample of aluminum that has a mass of 34.305 g? Fill in blanks.
00 G. You have two objects made of the same substance. Object 1 is a cube with a mass of 246.5 g. You measure the side of the cube using a ruler and find it to be 3.17 cm. Object 2 is a sphere with a mass of 123.3 g. You find the volume of the sphere using water displacement. The volume of the water in a graduated cylinder initially is 120.0 mL, and when the sphere is added the new volume is 135.8 mL. Which one of the following is the best reason for the difference between the two calculated densities? A) Different numbers of significant figures were used in each measurement. B) Uncertainty in measurement associated with the equipment. C) Errors in how the density was calculated. D) The units used to measure the densities are not the same. o search a 77°F delete 114 144 5. 6. D.
A nickel is found to have a mass of 4.87 grams. Using unit analysis, show what the mass of this nickel is in pounds. Use one of the following to set up the conversion factor. 454 g = 1 lb = 16 oz 1 m = 39.4 in= 3.28 feet 1 km = 0.621 mile 1 L = 1.06 qt 2.54 cm = 1 in 3.79 L=1 gal 4.87 grams X (number) 459 (number) lb Use the References to access important values if needed f g (unit) (unit) lb
In determining the density of a rectangular wooden block, use the information in the table below and the formula to fill in the empty boxes. (Apply the uncertainty rule) Volume of wooden block (cm3) = Length (cm) x Width (cm) x Thickness (cm) Mass (g) of wooden block (g) 20.5g Length of wooden block (cm) 5.00cm Width of wooden block (cm) 5.00cm Thickness of wooden block (cm) 1.00 cm Volume of wooden block (cm3) Density of wooden block (g/cm3) d = m/v
I don't understand the wording. The least significant digit means the last digit? 7.700 X 2.1 = 16.17 would the uncertainty be 0.01 ? 2.132 + 17 + 4.04 = 23.172 would the uncertainty be 0.001 ?