At the 95% level, test the hypothesis that the three samples A, B and C are drawn from the samepopulation?BLOCKS A1 50374723456344Select one:SAMPLESB23425433a. TS = 7.60 CV = 5.991b. TS= 6.80 CV = 5.991c. TS = 7.00 CV = 5.991d. TS 6.40 CV = 5.991=C3887534996

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Answered: At the 95% level, test the hypothesis…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Several methods of estimating the number of seeds in soil samples have been developed by ecologists. An article gave the accompanying data on the number of seeds detected by the direct method and by the stratified method for 27 soil specimens. Specimen Direct Stratified 1 21 7 2 34 38 3 0 7 4 60 58 5 20 54 6 61 61 7 40 27 8 7 7 9 14 7 10 94 100 11 1 0 12 67 58 13 78 67 14 21 54 Specimen Direct Stratified 15 34 27 16 0 0 17 38 38 18 18 14 19 94 94 20 1 14 21 40 47 22 21 21 23 0 0 24 7 14 25 14 40 26 18 14 27 40 78 Do the data provide sufficient evidence to conclude that the mean number of seeds detected differs for the two methods? Test the relevant hypotheses using ? = 0.05. (Use ?direct − ?stratified.) Find the test statistic. (Round your answer to two decimal places.) t = Find the df. (Round your answer down to the nearest whole number.) df = Use technology to find the P-value. (Round your answer to four…
According to data from the Tobacco Institute Testing Laboratory, a certain brand of cigarette contains an average of 1.4 milligrams of nicotine. An advocacy group questions this figure, and commissions an independent test to see if the the mean nicotine content is higher than the industry laboratory claims. The test involved randomly selecting n = 15 cigarettes, measuring the nicotine content (in milligrams) of each cigarette. The data is given below: 1.8, 1.8, 1.5, 1.1, 1.4, 1.3, 1.3, 1.4, 1.1, 1.3, 1.6, 1.2, 1.8, 1.4, 1.6; Download .csv file Not sure how to perform some of the tasks with R-Studio? Click to learn more (a) Do the data follow an approximately Normal distribution? Use alpha = 0.05. yes (b) Determine the P-value for this Normality test, to at least three decimal places. P (c) Choose the correct statistical hypotheses. O A. Ho: > 1.4, O B. Ho = 1.4, O C. Ho X = 1.4, O D. Ho: X = 1.4, ⒸE. Ho - 1.4 HA: > 1.4 OF. Ho: X > 1.4, HA: X < 1.4 HA: < 1.4 HA: 1.4 HA: X 1.4 HA: X <…
The following data represent petal lengths (in cm) for independent random samples of two species of iris. Petal length (in cm) of Iris virginica: x1; n1 = 36 5.2 5.6 6.1 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.8 5.2 5.2 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.6 1.8 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.5 (a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1=s1=x2=s2= (b) Let μ1 be the population mean for x1 and let μ2 be the population mean for x2. Find a 99% confidence interval for μ1 − μ2. (Round your answers to two decimal places.) lower limitupper limit
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A certain virus affects 0.7% of the population. A test used to detect the virus in a person is positive 87% of the time if the person has the virus (true positive) and 14% of the time if the person does not have the virus (false positive). Fill out the remainder of the following table and use it to answer the two questions below based on a total sample of 100,000 people. Virus No Virus TotalPositive Test Negative Test Total 100,000a) Find the probability that a person has the virus given that they have tested positive. Round your answer to the nearest hundredth of a percent and do not include a percent sign. % b) Find the probability that a person does not have the virus given that they test negative. Round your answer to the nearest hundredth of a percent and do not include a percent sign. %
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A sample of 10 observations taken from a normally distributed population yielded the following data.46 54 30 48 46 39 47 36 41 56
Several methods of estimating the number of seeds in soil samples have been developed by ecologists. An article gave the accompanying data on the number of seeds detected by the direct method and by the stratified method for 27 soil specimens. Specimen 1 2 3 4 5 6 7 8 9 10 11 12 13 14 Direct 21 33 0 60 20 61 40 8 13 93 1 68 77 21 Stratified 8 37 8 57 53 61 28 8 8 100 0 57 68 53 Specimen 15 Find the test statistic. (Round your answer to two decimal places.) t = 16 17 18 19 20 21 22 23 24 25 26 27 Direct Find the df. (Round your answer down to the nearest whole number.) df = 33 0 37 17 93 1 40 21 0 8 13 Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 17 40 Stratified 28 0 37 13 93 13 48 21 0 13 40 Do the data provide sufficient evidence to conclude that the mean number of seeds detected differs for the two methods? Test the relevant hypotheses using a = 0.05. (Use direct stratified.) 13 77
The data to the right are from independent simple random samples from three populations. Determine each of the following. Sample 1 Sample 2 Sample 3 3 3 3 a. SSTR b. MSTR c. SSE d. MSE e. F 4 2 1 8 a. SSTR= (Round to three decimal places as needed.) b. MSTR = (Round to three decimal places as needed.) c. SSE = (Round to three decimal places as needed.) d. MSE = (Round to three decimal places as needed.) e. F = (Round to three decimal places as needed.)

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At the 95% level, test the hypothesis that the three samples A, B and C are drawn from the same population? BLOCKS A 50 37 47 1 23 4 5 63 44 Select one: SAMPLES B 23 4 25 4 33 a. TS= 7.60 CV = 5.991 b. TS= 6.80 CV = 5.991 c. TS 7.00 CV = 5.991 Od. TS= 6.40 CV = 5.991 C 38 87 53 49 96