At standard temperature and pressure, a 1.00 mol sample of Argon gas is vented into a 22.4 L rigid box that already contains 1.00 mol of Nitrogen gas. We would expect that Argon gas to

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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At standard temperature and pressure, a 1.00 mol sample of Argon gas is vented into a 22.4 L rigid box that already contains 1.00 mol of Nitrogen gas. We would expect that Argon gas to

Expert Solution
Step 1

At standard temperature and pressure N2 act near about as an ideal gas. Argon is an ideal gas

Given that,

Volume occupied by nitrogen = 22.4L

Number of moles of Argon = 1.00

Standard temperature is 298.15K

Pressure in the box is:

     P×V=n×R×TP=n×R×T22.4LP=1×0.08205L.atmmole.K×273.15K22.4LP=1atm

After venting of 1 mole of Argon into the box,

Number of moles of gas = 2

Temperature of the gas = 273.15K

Volume of box =22.4 L

Pressure in the box is given by:

       P=n×R×TVP=2×0.08205L.atmmole.K×273.15K22.4LP=2atm

Therefore after venting off Argon into the box the pressure in the box increases.

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