Given, Mass of lighter initially: 13.948 g Final mass of lighter: 13.668 g Mass of fuel used: 0.28 g Temperature in C: 22.2 C Temperature in K: 295.35 K Volume of gas collected in mL: 93.5 mL Volume of gas collected in L: 0.0935 L Total pressure: 0.99956 atm Using a graph of ln P in mmHg versus 1/T where T is the temperature in Kelvin. The equation is y = -5206.4 x + 20.621 (With an R^2 = 0.9999) Using y = -5206.4x + 20.621 (With an R^2 = 0.9999) Find the; 1. Vapor pressure of water: 2. Pressure of fuel: 3. Pressure of fuel in atm:
Given, Mass of lighter initially: 13.948 g Final mass of lighter: 13.668 g Mass of fuel used: 0.28 g Temperature in C: 22.2 C Temperature in K: 295.35 K Volume of gas collected in mL: 93.5 mL Volume of gas collected in L: 0.0935 L Total pressure: 0.99956 atm Using a graph of ln P in mmHg versus 1/T where T is the temperature in Kelvin. The equation is y = -5206.4 x + 20.621 (With an R^2 = 0.9999) Using y = -5206.4x + 20.621 (With an R^2 = 0.9999) Find the; 1. Vapor pressure of water: 2. Pressure of fuel: 3. Pressure of fuel in atm:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given,
Mass of lighter initially: 13.948 g
Final mass of lighter: 13.668 g
Mass of fuel used: 0.28 g
Temperature in C: 22.2 C
Temperature in K: 295.35 K
Volume of gas collected in mL: 93.5 mL
Volume of gas collected in L: 0.0935 L
Total pressure: 0.99956 atm
Using a graph of ln P in mmHg versus 1/T where T is the temperature in Kelvin. The equation is y = -5206.4 x + 20.621 (With an R^2 = 0.9999)
Using y = -5206.4x + 20.621 (With an R^2 = 0.9999)
Find the;
1. Vapor pressure of water:
2. Pressure of fuel:
3. Pressure of fuel in atm:
4. Molar mass of fuel :
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