at R+T=1i
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![2. I showed in class that the reflection coefficient for TE waves is r =
transmission coefficient is t = t
=
2 n₁ cos B₁
Bi n₁ cos i + n₂ cos 6+
wwwww
n₁ cose-n₂ cos et
=
and
E₁
n₁ cose; + ng cos et
. Further, I mentioned that the reflectivity is
R = I did not, however, claim that the transmissivity is T = | because T
.
'
#
Incident light is either reflected or transmitted. Therefore, using the concept of energy flow, we
should have (S₂). = −(S) · n + (S) · ŵ, where n is the unit normal pointing from Medium 1
to Medium 2 (see sketch below). Using the formula derived in Problem 1 and r and t above, show
that (S) = -(S) + (St) ŵn is indeed true. The reflectivity is actually defined as R =
and the transmissivity is T =
|(S)-|
. Verify that R+T = 1 is also true for TM waves.
| (Si)-n|*
(Si)
(S,-)
|(S,)-n|
| (Si)-|
E
n
(St)
|](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F747ab200-c676-4ed9-b814-dae7641fcf0c%2F3c1bad86-32b4-48af-ae22-7bc6452ce1d4%2F96zkkss_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. I showed in class that the reflection coefficient for TE waves is r =
transmission coefficient is t = t
=
2 n₁ cos B₁
Bi n₁ cos i + n₂ cos 6+
wwwww
n₁ cose-n₂ cos et
=
and
E₁
n₁ cose; + ng cos et
. Further, I mentioned that the reflectivity is
R = I did not, however, claim that the transmissivity is T = | because T
.
'
#
Incident light is either reflected or transmitted. Therefore, using the concept of energy flow, we
should have (S₂). = −(S) · n + (S) · ŵ, where n is the unit normal pointing from Medium 1
to Medium 2 (see sketch below). Using the formula derived in Problem 1 and r and t above, show
that (S) = -(S) + (St) ŵn is indeed true. The reflectivity is actually defined as R =
and the transmissivity is T =
|(S)-|
. Verify that R+T = 1 is also true for TM waves.
| (Si)-n|*
(Si)
(S,-)
|(S,)-n|
| (Si)-|
E
n
(St)
|
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