Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
At point A (4.0) a mass of 3 kg is placed and at point B (8.0) another mass of 5 kg is placed. Calculate the resultant force acting on a third mass of 7 kg when it is placed at the origin of coordinates and when it is located at point C (1,3).

At point A (4.0) a mass of 3 kg is placed and at point B (8.0) another mass of 5 kg is placed. Calculate the resultant force acting on a third mass of 7 kg when it is placed at the origin of coordinates and when it is located at point C (1,3).

icon
Related questions
Question

At point A (4.0) a mass of 3 kg is placed and at point B (8.0) another mass of 5 kg is placed. Calculate the resultant force acting on a third mass of 7 kg when it is placed at the origin of coordinates and when it is located at point C (1,3).

Expert Solution
Step 1

Given,

masses are,

m1=3kgm2=5kg

where mass m1 is placed at point A = A(4,0). and mass m2 is placed at point B = B(8,0).

a)

A third mass m3 is placed at origin "O". where m3 = 7(kg). 

The distance between m1 and m3 will be, r→31=0-4x^=-4x^

And the distance between m2 and m3 will be, r→32=0-8x^=-8x^

So the force on m3 due to m1 will be,

F→31=-Gm1m3r→312r^31=-6.67408×10-11N.m2/kg2×3kg×7kg16-x^=8.75×10-11Nx^

Advanced Physics homework question answer, step 1, image 1

the force on m3 due to m2 will be,

F→32=-Gm1m3r→322r^32=-6.67408×10-11N.m2/kg2×5kg×7kg64-x^=3.61×10-11Nx^

So, the net force on m3 will be,

F→3=F→31+F→32=8.75×10-11N+3.61×10-11Nx^=12.36×10-11Nx^

 

 

 

 

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer