A parachuter of mass 139 kg above Earth (g = 10 m/s2) experiences a drag force modeled by -0.04 v (N).  If the parachuter is released from rest, how fast, in m/s, will the jumper be falling after 1,027 s? (Assume the parachuter doesn't reach the ground in this amount of time.)

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A parachuter of mass 139 kg above Earth (g = 10 m/s2) experiences a drag force modeled by -0.04 v (N).  If the parachuter is released from rest, how fast, in m/s, will the jumper be falling after 1,027 s? (Assume the parachuter doesn't reach the ground in this amount of time.)(I want the speed.)

(Please answer to the fourth decimal place - i.e 14.3225)

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From Newton's second law of motion

mg-kv=mdvdt0vdvmg-kv=0tdtm-1klnmg-kvmg=tmmg-kvmg=e-ktmv=mgk1-e-ktm

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