At node 1, in the circuit below, Applying KCL gives:(use current directions at node 1)( 2 A82V1V212 V62Select one:V-12 0-V.!V2-VI2+6.4a.V2- VI4VI-12оь. 2 +312 v 0-VI, V-V2O c 2+3%3D6.412 - V V3Od. 2+.%D4ww

Answered: Image /qna-images/answer/ed7b1416-81fa-450f-98af-fdca4e1f027b.jpg

At node 1, in the circuit below, Applying KCL gives: (use current directions at node 1) 12 V Select one: O a. 2+ О ь. 2 + O c. 2+ 2+1 3 1¹²2=0 / 6 30 www d. 2+. 60 V₁-12 12-0- 0-1+1/2"1 3 6 V₁ - 12 V₁, V2 - V1 4 12-V₁_0-V1 + V₁ VI 3 3 2 A 6 12-1-1+"="² V₁ 6 4 4 4 40 ww V₂ 12 2 89 V2 692

At node 1, in the circuit below, Applying KCL gives: (use current directions at node 1) 12 V Select one: O a. 2+ О ь. 2 + O c. 2+ 2+1 3 1¹²2=0 / 6 30 www d. 2+. 60 V₁-12 12-0- 0-1+1/2"1 3 6 V₁ - 12 V₁, V2 - V1 4 12-V₁_0-V1 + V₁ VI 3 3 2 A 6 12-1-1+"="² V₁ 6 4 4 4 40 ww V₂ 12 2 89 V2 692

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter17: Current And Resistance

Section: Chapter Questions

Problem 40P: A typical cell phone consumes an average of about 1.00 W of electrical power and operates on 3.80 V....

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