At high temperatures, iodine molecules can dissociate into iodine atoms. For the reaction l2(g) 2 1 (g) Kc = 1.27 x 10 at 900 °C. A 50.5 g sample of l₂ is placed in a 1.00 L vessel and heated to 900 °C. What will be the molar concentration of iodine atoms, [1], in the vessel when the system comes to equilibrium?

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.51QE
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At high temperatures, iodine molecules can dissociate into iodine atoms. For the reaction I₂(g) ⇌ 2 I・(g) Kc = 1.27 × 10⁻⁴ at 900 °C. A 50.5 g sample of I₂ is placed in a 1.00 L vessel and heated to 900 °C. What will be the molar concentration of iodine atoms, [I・], in the vessel when the system comes to equilibrium?

At high temperatures, iodine molecules can dissociate into iodine atoms. For the reaction l₂(g) → 2 1 (g) Kc = 1.27 × 10-4 at 900 °C. A 50.5 g sample of 12 is placed in a 1.00 L vessel and heated to 900
°C. What will be the molar concentration of iodine atoms, [1], in the vessel when the system comes to equilibrium?
Transcribed Image Text:At high temperatures, iodine molecules can dissociate into iodine atoms. For the reaction l₂(g) → 2 1 (g) Kc = 1.27 × 10-4 at 900 °C. A 50.5 g sample of 12 is placed in a 1.00 L vessel and heated to 900 °C. What will be the molar concentration of iodine atoms, [1], in the vessel when the system comes to equilibrium?
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