At an altitude of 15 km the temperature is 217 K and the pressure 12.1 kPa. What is the mean free path of N2 molecules? Note: Cross-sectional Area for Nitrogen is 0.43 nm2 when the Cross-sectional Area = d2π

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Q: At an altitude of 15km the temperature is 217 K and the pressure is 12.1 kPa. What is the mean free…

A: Given pressure = 12.1 kPa Temperature = 217°K σ = 0.43 nm2

Q: At a height of 15 kilometers, the temperature is 217K and the pressure is 12.1 kPa. What is the mean…

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Q: At an altitude of 20 km the temperature is 217 K and the pressure is 0.050 atm. What is the mean…

A: Introduction :  We have to calculate mean free path of N2 molecules . Given :  Pressure = 0.050 atm…

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A: Mean Free Path is the average distance traveled by a moving molecule between collisions. N2 is a…

Q: At an altitude of 15 km the temperature is 217 K and the pressure is 12.1 kPa. What is the mean free…

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Q: Compare the mean free path of an N2 molecule at an altitude of 15km where the temperature is 217 K…

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Q: At an altitude of 20 km, the temperature is 217 K, and the pressure is 0.050 atm. Taking the cross…

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A: 1.00 dm3 = 1000 cm3 By Charles law : T2T1 =V2V1  T2(22.2 + 273.15) = 100 cm31000 cm3   T2 = 29.535 K…

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