At a potential of –1.0 V (versus SCE), carbon tetrachloride in methanol is reduced to chloroform at a Hg cathode: 2CCI, + 2H* + 2e¯+ 2Hg(1) → 2CHCI, + Hg,Cl,(s) At –1.80 V, the chloroform further reacts to give methane: 2CHCI, + 6H+ + 6e¯+ 6Hg(1) 2CH, + 3Hg,Cl,(s) Several 0.750-g samples containing CCl,, CHCI3, and inert organic species were dissolved in methanol and electrolyzed at –1.0 V until the current approached zero. A coulometer indicated the charge required to complete the reaction, as given in the second column of the following table. The potential of the cathode was then adjusted to –1.80 V. The additional charge required to complete the reaction at this potential is given in the third column of the table Calculate the percent CCI, and CHCI, in each mixture,

At a potential of –1.0 V (versus SCE), carbon tetrachloride in methanol is reduced to chloroform at a Hg cathode: 2CCI, + 2H* + 2e¯+ 2Hg(1) → 2CHCI, + Hg,Cl,(s) At –1.80 V, the chloroform further reacts to give methane: 2CHCI, + 6H+ + 6e¯+ 6Hg(1) 2CH, + 3Hg,Cl,(s) Several 0.750-g samples containing CCl,, CHCI3, and inert organic species were dissolved in methanol and electrolyzed at –1.0 V until the current approached zero. A coulometer indicated the charge required to complete the reaction, as given in the second column of the following table. The potential of the cathode was then adjusted to –1.80 V. The additional charge required to complete the reaction at this potential is given in the third column of the table Calculate the percent CCI, and CHCI, in each mixture,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

At a potential of –1.0 V (versus SCE), carbon tetrachloride in methanol is reduced to chloroform at a Hg
cathode:
2CCI, + 2H*+ 2e¯+ 2Hg(1)
→ 2CHCI, + Hg,Cl,(s)
At -1.80 V, the chloroform further reacts to give methane:
2CHCI, + 6H+ + 6e¯+ 6Hg(1)
→ 2CH, + 3Hg,Cl,(s)
Several 0.750-g samples containing CCL4, CHCI,, and inert organic species were dissolved in methanol and
electrolyzed at -1.0 V until the current approached zero. A coulometer indicated the charge required to
complete the reaction, as given in the second column of the following table. The potential of the cathode
was then adjusted to -1.80 V. The additional charge required to complete the reaction at this potential is
given in the third column of the table. Calculate the percent CCl, and CHCI, in each mixture.
Charge Required
at –1.0 V, C
Charge Required
at –1.8 V, C
Sample No.
1
10.84
69.20
2
20.52
88.50
3
6.22
45.98
4
11.60
68.62

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