At a point in an elastic material there are two mutually perpendicular planes, one of which carries a direct tensile stress of 50 N/mm² and a shear stress of 40 N/mm² while the other plane is subjected to a direct compressive stress of 35 N/mm² and a complementary shear stress of 40 N/mm². Determine the principal stresses at the point, the position of the planes on which they act and the position of the planes on which there is no direct stress. Ans. o1 = 65.9 N/mm², 0 = -21.6°, o1=-50.9 N/mm², 0 = -111.6°. No direct stress on planes at 27.1° and 117.1° to the plane on which the 50 N/mm2 stress acts.

Q: At a point in elastic medium normal stresses in two mutually perpendicular directions are 120 MPa,…

A: Normal stresses : = 120 MPa = 40 MPaTangential stress = 30 MPaTo Find :Principal stresses ?

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A: Consider the free body diagram;Given;Young modulus, E=Poisson ratio, v=0.3

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A:

Q: Question 4 At a point in a thin steel plate in plane stress (0z = Txz= Tyz= 0), Ex=600, &y= - 2004µ…

A: E=2G1+ν=276.921+0.3=200Gpa

Q: A homogenous isotropic material of size 20 cm x 20 cm x 20 cm is placed inside a rigid box of…

A:

Q: 2. Which of the below stresses are normal stresses? a) Tensile and compressive stresses b) Tensile…

A: Which of the below stresses are normal stresses? a) Tensile and compressive stresses

Q: (c) A piece of material is subjected to tensile stress of 70 N/mm² in one direction and a…

A: Given:σx=70 N/mm2σy=-50 N/mm2Sign convention:Tensile stress: Positive+Compressive stress: Negative-.

Solid Mechanics

Engineering mechanics is a branch of science that deals with forces causing bulk motion in bodies and the effect that these forces cause on the bodies. Engineering mechanics does not deal with the internal changes that occur on account of these external forces. The internal effects in a body or a material under the action of external forces are studied in a new branch of science called solid mechanics, the strength of materials, or the mechanical behavior of engineering materials.