At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressure (in atm) of He would give a solubility of 0.370 M?
At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressure (in atm) of He would give a solubility of 0.370 M?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Question 3 of 16
At a particular temperature, the solubility of He in water is 0.080 M when the
partial pressure is 1.7 atm. What partial pressure (in atm) of He would give a
solubility of 0.370 M?
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Expert Solution

Step 1: Statement for Henry's Law
Henry’s law states that the solubility of a gas in a liquid is proportional to the partial pressure of the gas on the surface of the liquid. Henry's law can be expressed mathematically as follows
Where;
- P is the partial pressure of the gas (in atm)
- KH is the Henry's law constant for the gas-liquid system
- C is the concentration/solubility of the gas in the liquid (in mol/L)
Provided, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. i.e. the Henry’s law constant for the He-water system at this temperature is calculated as
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