Question 3 of 16At a particular temperature, the solubility of He in water is 0.080 M when thepartial pressure is 1.7 atm. What partial pressure (in atm) of He would give asolubility of 0.370 M?Tap here or pull up for additional resources147+/-atm2 356890SubmitXCx 100

Answered: At a particular temperature, the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Step 1: Statement for Henry's Law

Henry’s law states that the solubility of a gas in a liquid is proportional to the partial pressure of the gas on the surface of the liquid. Henry's law can be expressed mathematically as follows

$bold italic P bold italic cross times bold italic K subscript bold italic H bold italic equals bold italic s bold italic o bold italic l bold italic u bold italic b bold italic i bold italic l bold italic i bold italic t bold italic y bold rightwards arrow bold left parenthesis bold 1 bold right parenthesis$

Where;

P is the partial pressure of the gas (in atm)
K_H is the Henry's law constant for the gas-liquid system
C is the concentration/solubility of the gas in the liquid (in mol/L)

Provided, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. i.e. the Henry’s law constant for the He-water system at this temperature is calculated as $bold italic K subscript bold italic H bold italic equals fraction numerator bold italic 0 bold italic. bold italic 080 bold italic space bold italic M bold italic space over denominator bold italic 1 bold italic. bold italic 7 bold italic space bold italic a bold italic t bold italic m end fraction bold italic space bold italic rightwards double arrow bold italic space bold italic 0 bold italic. bold italic 0470 bold italic space bold italic M bold italic. bold italic a bold italic t bold italic m to the power of bold italic minus bold italic 1 end exponent$

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