At a certain temperature the rate of this reaction is first order in NH, with a rate constant of 1.22 s : 2NH; (g) → N, (3) + 3H, (2) Suppose a vessel contains NH, at a concentration of 0.450M. Calculate the concentration of NH, in the vessel 0.860 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits. ?

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### Reaction Rate and Concentration Calculation

At a certain temperature, the rate of this reaction is first order in \( \text{NH}_3 \) with a rate constant of \( 1.22 \ s^{-1} \):

\[
2\text{NH}_3 \ (g) \rightarrow \text{N}_2 \ (g) + 3\text{H}_2 \ (g)
\]

Suppose a vessel contains \( \text{NH}_3 \) at a concentration of \( 0.450 \ M \). Calculate the concentration of \( \text{NH}_3 \) in the vessel \( 0.860 \) seconds later. You may assume no other reaction is important.

Round your answer to 2 significant digits.

____

\(\boxed{\phantom{0}M}\) \[\checkmark_{x10}\]

**Explanation:**

1. **Identify the Reaction Order and Rate Constant:**
   - The reaction is first order in \( \text{NH}_3 \) (ammonia).
   - The rate constant \( k \) is \( 1.22 \ s^{-1} \).

2. **Initial Concentration:**
   - Initial concentration of \( \text{NH}_3 \) is \( [\text{NH}_3]_0 = 0.450 \ M \).

3. **Use the First Order Reaction Formula:**
   - The formula for first-order reactions is:
     \[
     [\text{NH}_3] = [\text{NH}_3]_0 e^{-kt}
     \]

4. **Substitute the Given Values:**
   - Time \( t \) is \( 0.860 \) seconds.
   - Substitute into the formula:
     \[
     [\text{NH}_3] = 0.450 \ M \times e^{-1.22 \times 0.860}
     \]

5. **Calculate:**
   - Calculate the exponent:
     \[
     -1.22 \times 0.860 \approx -1.0492
     \]
   - Calculate \( e^{-1.0492} \):
     \[
     e^{-1.0492} \approx 0.350
     \]
   - Final concentration:
     \[
     [\text{NH}_3] \approx 0.450 \ M
Transcribed Image Text:### Reaction Rate and Concentration Calculation At a certain temperature, the rate of this reaction is first order in \( \text{NH}_3 \) with a rate constant of \( 1.22 \ s^{-1} \): \[ 2\text{NH}_3 \ (g) \rightarrow \text{N}_2 \ (g) + 3\text{H}_2 \ (g) \] Suppose a vessel contains \( \text{NH}_3 \) at a concentration of \( 0.450 \ M \). Calculate the concentration of \( \text{NH}_3 \) in the vessel \( 0.860 \) seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits. ____ \(\boxed{\phantom{0}M}\) \[\checkmark_{x10}\] **Explanation:** 1. **Identify the Reaction Order and Rate Constant:** - The reaction is first order in \( \text{NH}_3 \) (ammonia). - The rate constant \( k \) is \( 1.22 \ s^{-1} \). 2. **Initial Concentration:** - Initial concentration of \( \text{NH}_3 \) is \( [\text{NH}_3]_0 = 0.450 \ M \). 3. **Use the First Order Reaction Formula:** - The formula for first-order reactions is: \[ [\text{NH}_3] = [\text{NH}_3]_0 e^{-kt} \] 4. **Substitute the Given Values:** - Time \( t \) is \( 0.860 \) seconds. - Substitute into the formula: \[ [\text{NH}_3] = 0.450 \ M \times e^{-1.22 \times 0.860} \] 5. **Calculate:** - Calculate the exponent: \[ -1.22 \times 0.860 \approx -1.0492 \] - Calculate \( e^{-1.0492} \): \[ e^{-1.0492} \approx 0.350 \] - Final concentration: \[ [\text{NH}_3] \approx 0.450 \ M
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