At a certain temperature, the equilibrium constant for the following reaction is o.0472. All gases are at an initial pressure of o.862 atm, for the following reaction: NO(g) + SO, (g) + S0, (g) + NO,(g) Solve for the change in partial pressure Solve for the partial pressure of NO atm Solve for the partial pressure of SO, atm Solve for the partial pressure of SO, atm atm Solve for the partial pressure of NO, atm Determine the initial total partial pressure for the gases atm Determine the total partial pressure for the gases at equilibrium

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Chapter1: Chemical Foundations
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At a certain temperature, the equilibrium constant for the following reaction is o.0472.
All gases are at an initial pressure of o.862 atm, for the following reaction:
NO(g) + SO, (g) → SO, (g) + NO,2(g)
Solve for the change in partial pressure
Solve for the partial pressure of NO
atm
Solve for the partial pressure of SO,
atm
Solve for the partial pressure of SO,
atm
Solve for the partial pressure of NO,
atm
atm
Determine the initial total partial pressure for the gases
atm
Determine the total partial pressure for the gases at equilibrium
This relationship would be true when the change in the number of moles of gases remains the same
Transcribed Image Text:At a certain temperature, the equilibrium constant for the following reaction is o.0472. All gases are at an initial pressure of o.862 atm, for the following reaction: NO(g) + SO, (g) → SO, (g) + NO,2(g) Solve for the change in partial pressure Solve for the partial pressure of NO atm Solve for the partial pressure of SO, atm Solve for the partial pressure of SO, atm Solve for the partial pressure of NO, atm atm Determine the initial total partial pressure for the gases atm Determine the total partial pressure for the gases at equilibrium This relationship would be true when the change in the number of moles of gases remains the same
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