At a certain temperature, 0.301 mol CH, and 0.688 mol H₂O is placed in a 2.50 L container. CH₂(g) + 2 H₂O(g) = CO₂(g) + 4H₂(g) At equilibrium, 8.71 g CO, is present. Calculate K.. K₂ =

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Chapter13: Chemical Equilibrium
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At a certain temperature, 0.301 mol CH, and 0.688 mol H₂O is placed in a 2.50 L container.
CH₂(g) + 2 H₂O(g) = CO₂(g) + 4H₂(g)
At equilibrium, 8.71 g CO, is present. Calculate K.
K₂ =
Check Answer
53
Transcribed Image Text:Question 8 of 21 > At a certain temperature, 0.301 mol CH, and 0.688 mol H₂O is placed in a 2.50 L container. CH₂(g) + 2 H₂O(g) = CO₂(g) + 4H₂(g) At equilibrium, 8.71 g CO, is present. Calculate K. K₂ = Check Answer 53
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