At a certain excavation site, archaeological studies have used the method of tree-ring dating in an effort to determine when people lived in there. Wood from several excavations gave a mean of (year) 1305 with a standard deviation of 22 years. The distribution of dates was more or less mound-shaped and symmetrical about the mean. Use the empirical rule to estimate a range of years centered about the mean in which about 68.3% of the data (tree-ring dates) will be found. Group of answer choices from 1239 to 1283 from 1305 to 1349 from 1239 to 1327 from 1327 to 1371 from 1283 to 1327

Q: Average income

A: This data is the Average income by County for 2014 and 2018. the given information is showing the…

Q: Consider a sample with a mean of 500 and a standard deviation of 100. What are the z-scores for the…

A: The mean is 500 and the standard deviation is 100.

Q: Suppose a small paint manufacturing company has a daily production that is normally distributed with…

A: Solution: It is given that a small paint manufacturing company has a daily production that is…

Q: Dr. Samwell Tarly wants to estimate the number of books checked out of the library in the past year.…

A: It is given that the mean is 10,000 and the standard deviation is 10.

Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…

A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

Q: Suppose that striped dolphin lengths are normally distributed with a population standard deviation…

A: The formula for the minimum sample size is as follows: Here, zα/2 is the critical value at 95%…

Q: Steel rods are manufactured with a mean length of 25 centimeters (cm). Because of the variability in…

A: Given, Steel rod length are normally distributed with mean 25 cm and standard deviation 0.07.

Q: Do the data support your claim at the 1% level?

A: The summary of the statistics is, The type of test is right tailed test

Q: 58.6. Assume that 107 men and 244 women were sampled, and that the standard deviations were 24.3 for…

A: Given that, The Pew Internet and American Life Project surveyed 351 adults in 2019, asking them…

Q: Suppose the distribution of typing speeds in words per minute for experienced typists can be…

A: The provided information is:

Q: Two different species of trees have heights that are approximately normal in distribution.  Tree A…

A: The z-score of a random variable x is defined as follows: z = (x – µ)/σ. Here, µ and σ are the mean…

Q: Suppose that a study of elementary school students reports that the mean age at which children begin…

A: The provided information are: Population mean (µ) = 5.7 Population standard deviation (σ) = 1.2…

Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…

A: Let X be the length of the steel rods. Then X~N (144.3,0.8) i.e. µ=144.3 and σ=0.8

Q: on Learning Find the margins of error for 95% confidence based on SRSS of 400 young men and 1600…

A: Let  be the population mean BMI.Given that,Sample mean Sample size Population standard deviation…

Q: Given the mean of a normally distributed data set is 25, with  standard deviation of 5, what percent…

A: We will standardize the normal variable and then use standard Normal table to find the required.

Q: If an espresso machine out-pour is normally distributed with the mean of 0.9 ounces and standard…

A: Let  X be the random variable from normal distribution with mean (μ) = 0.9 and standard deviation…

Q: The lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days…

A:

Q: Suppose the average golfer drives the ball around 259.1 yards with a standard deviation of 9.73.…

A: Solution

Q: Suppose the mean height of women age 20 years or older in a certain country is 62.7 inches. One…

A: We have given that The null and alternative hypothesis are H0 : µ = 62.7Ha : µ ≠ 62.7 The test…

Q: Consider the variable, type of birth control practiced (e.g., an IUD, condoms, none, etc). Which…

A:

Q: A researcher is conducting a study to determine the mean trough dosage of medication for a…

A: The following information is provided that is required to compute the sample size: Required…

Q: calculate that the mean age of students, where 30 is the mean and standard deviation is 6. Between…

A:

Q: Sketch the distribution of heights. What percentage of students are over 73.38 inches tall? What…

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: A researcher collected data on the palate length of 50 individual shrews of the same species.. She…

A: In this question, a researcher has collected data on the palate length of 50 individual shrews of…

Q: Suppose you organized a​ 10-kilometer race in which the times were normally distributed with a mean…

A: Let X be any selected finishing time. Here, we have to find the percentage of runners took longer…

Q: The National Center for Health Statistics reports that the LDL cholesterol for adults has a mean of…

A: Sample size n=23 Sample mean=144.3 Population standard deviation =40

Q: The lengths of pregnancies in a small rural village are normally distributed with a mean of 270 days…

A: Let "X" be the lengths of pregnancies in a small rural village in days.

Q: An article in the San Jose Mercury Newsstated that students in the California state university…

A:

Q: Suppose a small paint manufacturing company has a daily production that is normally distributed with…

A:

Q: Use the formula Ỹ - to.05(2),df SE < μ< Ỹ + 10.05(2),df SE to calculate a 95% confidence interval…

A: sample size = n = 23 blind individualssample mean=standard deviation =

Q: Suppose that the heights of 4-year old boys are normally distributed with a mean of 103cm and a…

A: Let X be the random variable from normal distribution with mean (μ) = 103 cm and standard deviation…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.