At 95% confidence interval, test the hypothesis that the mean for allmachine are significantly different from each other.Machine AMachine BMachine C435355564753565155495251616164655551

using the given data, At 5% significance level we have to test the hypothesis that the mean for all…

Answered: At 95% confidence interval, test the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Population 2 Use the given statistics to complete parts (a) and (b). Assume that the populations are normally distributed. (a) Test whether u, > Hz at the a = 0.01 level of significance for the given sample data. (b) Construct a 95% confidence interval about u1 - H2. Population 1 29 23 45.6 42.9 4.1 11.8 O A. Ho: H1 = #2 H1: H1 # H2 YB. Ho: H1 = H2 H: H1> H2 O C. Ho: H1>H2 H: H1 =H2 O D. Ho: H1 H2. B. Do not reject Ho. There is not sufficient evidence at the a = 0.01 level of significance to conclude that u, > u2. O C. Reject Ho. There is sufficient evidence at the a = 0.01 level of significance to conclude that u, >H2. O D. Reject Ho. There is not sufficient evidence at the a = 0.01 level of significance to conclude that u1 > H2. (b) The 95% confidence interval about u, - uz is the range from a lower bound of to an upper bound of (Round to three decimal places as needed.)
Test the claim that the samples come from populations with the same mean. Assume that the populations are normally distributed with the same variance. At the 0.025 significance level, test the claim that the four brands have the same mean if the following sample results have been obtained. Brand A Brand B Brand C Brand D 21 24 22 17 20 21 18 25 27 29 35 18 23 25 22 25 26 29 29 21 26 36 37
Using ANOVA example on body temperature for different age groups, test whether these programmers commit same number of errors on average. State Ho vs Ha Test statistic
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Infectious Disease Commonly used vaccines for influenza are trivalent and contain only one type of influenza B virus. They may be ineffective against other types of influenza B virus. A randomized clinical trial was performed among children 3 to 8 years of age in 8 countries. Children received either a quadrivalent vaccine (QIV) that had more than one influenza B virus or a trivalent Hepatitis A vaccine (control). An attack rate (i.e.,% of children who developed influenza) starting 14 days after vaccination until the end of the study was computed for each vaccine group, stratified by age. The following data were reported. age QIV group 3-4 5-8 3.75 1.71 Control group 5.64 5.17 (a) Suppose 3 children in a village ages 3, 5, and 7 are vaccinated with the QIV vaccine. What is the probability that at least one child among the 3 will get influenza? (Round your answer to four decimal places.) (b) Suppose that 80% of 3-4-year-old children and 70% of 5-8-year-old children in a village are…
Chocolate Chip Cookie Calories The average 1-ounce chocolate chip cookie contains 110 calories. A random sample of 14 different brands of 1- ounce chocolate chip cookies resulted in the following calorie amounts. At the a=0.10 level, is there sufficient evidence that the average calorie content is greater than 110 calories? Assume the population is normally distributed. 100 105 160 110 Send data to Excel Part 1 of 5 (a) State the hypotheses and identify the claim. Ho: 110 claim H₁: 110 not claim This hypothesis test is a one-tailed Correct Answer: Ho: μ = 110 not claim H₁: μ> 110 claim This hypothesis test is a one-tailed test. Part 2 of 5 Correct Answer: (b) Find the critical value(s). Round the answer to three decimal places, if necessary. If there is more than one critical value, separate them with commas. Critical value(s): 2.624) Critical value: 1.350 115 115 150 120 190 120 152 100 135 153 Part: 2 / 5 Part 3 of 5 t = test. (c) Compute the test value. Round the sample statistics…
5 Hypothesis Test It is conjectured that the proportion of all people who went trick-or-treating who also had a pumpkin carved into a jack-o'-lantern at their home is 0.62. Of interest is to test this claim versus the alternative that the proportion of all people who went trick-or-treating who also had a pumpkin carved into a jack-o'-lantern at their home is less than 0.62. A simple random sample of 270 people who went trick-or-treating is selected, and 162 of them also had a pumpkin carved into a jack-o'-lantern at their home (and the other 108 did not). If appropriate, use this information to test if the proportion of all people who went trick-or-treating who also had a pumpkin carved into a jack-o'-lantern at their home is less than 0.62 at the a = .10 level of significance. A simple random sample of 270 people who went trick-or-treating is selected, and 162 of them also had a pumpkin carved into a jack-o'-lantern at their home (and the other 108 did not). use this information to…
Cost of shopping Do consumers spend more on a trip toWalmart or Target? Suppose researchers interested in thisquestion collected a systematic sample from 85 Walmartcustomers and 80 Target customers by asking customersfor their purchase amount as they left the stores. The datacollected is summarized in the table below.To perform inference on these two samples, what condi-tions must be met? Are they? Explain. Walmart Targetn 85 80y $45 $53s $21 $19
Pretend you have the following data for 16 subjects in a study designed to determine whether strong coffee speeds neural processing, in this case defined as reaction time in a simple memory task, with lower numbers reflecting faster processing. The 16 subjects were randomly assigned to two groups: placebo control group vs. coffee experimental group. Here are the results, followed by guidance for the VassarStats program: Placebo Coffee 28 26 23 18 20 15 28 24 29 24 33 19 34 13 http://vassarstats.net/ #1. What is the null hypothesis for this study? #2. a. State the mean for each group: Placebo mean = ?? Coffee mean = ?? b. What is the mean difference? #3. a. What was the level of significance (two-tailed p value)? b. What, then, is the probability that “chance” explained this mean difference given that p value? #4. a. What is your decision regarding the null hypothesis…
A recipe submitted to a magazine by one of its subscribers states that the mean baking time for a cheesecake is 57 minutes. A test kitchen preparing the recipe before it is published in the magazine makes the cheesecake 12 times at different times of the day in different ovens. The following baking times (in minutes) are observed. 52 54 55 57 60 63 64 64 66 64 65 66 Assume that the baking times belong to a normal population. (a) Test the null hypothesis that the mean baking time is 57 minutes against the alternative hypothesis 57. Use a=.05. (b) What is the P value?

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At 95% confidence interval, test the hypothesis that the mean for all machine are significantly different from each other. TTT Machine A Machine B Machine C 43 53 55 56 47 53 56 51 55 49 52 51 61 61 64 65 55 51