At 850 K, the equilibrium constant for the reaction 2 S0,( +0,() - 2 So,(g) is K- 15. If the given concentrations of the three gases are mixed, predict in which direction the net reaction will proceed toward equilibrium. Left No net reaction Right Answer Bank (S0,1-020 M 10,1-0.60 M (S0,) 0.60 M [SO,1-0IN M 10,1-0.10 M (SO,)-0.50 M ISO,-050 M IS0,1-0.15 M W ovool

At 850 K, the equilibrium constant for the reaction 2 S0,( +0,() - 2 So,(g) is K- 15. If the given concentrations of the three gases are mixed, predict in which direction the net reaction will proceed toward equilibrium. Left No net reaction Right Answer Bank (S0,1-020 M 10,1-0.60 M (S0,) 0.60 M [SO,1-0IN M 10,1-0.10 M (SO,)-0.50 M ISO,-050 M IS0,1-0.15 M W ovool

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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When determining the equilibrium concentrations for the reaction [A][B] AB(g) = A(g) + B(g) [AB] a simplifying assumption can be used under certain conditions to avoid solving a quadratic equation. x2 K. = [AB] - x [AB] Classify each situation by whether the simplifying assumption can be used or whether the quadratic formula is required. Simplifying assumption can be used Quadratic formula required Answer Bank [AB] = 0.2209 M, Ke = 4.5 × 10-6 [AB] = 0.0394 M, Ke = 8.12 × 10-5 [AB] = 0.00103 M, K. = 7.4 × 10¬8 [AB] = 0.0207 M, Ke = 2.88 × 10-6 [AB] = 0.243 M, Ke = 7.11 × 10¬4
When determining the equilibrium concentrations for the reaction AB(g) A(g) + B(g) [A][B] [AB] a simplifying assumption can be used under certain conditions to avoid solving a quadratic equation. Ke Kc = [AB]-x [AB] Classify each situation by whether the simplifying assumption can be used or whether the quadratic formula is required. Simplifying assumption can be used [AB] = 0.00178 M. Kc = 9.91 x 107 [AB]=0.0353 M, K, 3.67 x 10 Answer Bank [AB]=0.484 M, K, 8.18 x 10 Quadratic formula required [AB] 0.176 M. K=144 x 10¹ [AB]=0.0160 M, K - 7.46 x 10
CO to Withdr... Forms | Office of t... Content $ 4 Submit Answer 000 DOD F4 R The equilibrium constant, Kc, for the following reaction is 5.10 x 10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) F X % Show Hint 5 If an equilibrium mixture of the three compounds in a 4.30 L container at 548 K contains 1.72 mol of NH4Cl(s) and 0.323 mol of NH3, the number of moles of HCl present is mol. 2 Bh Salinger Pages T KB Viewing Your Aca... Have F5 Retry Entire Group 9 more group attempts remaining [Review Topics] [References] Use the References to access important values if needed for this question. Cengage Learning Cengage Technical Support A X OWLv2 | Online X t 6 - in... Have Changes in... Scholarship Ameri... Changes MacBook Air F6 Y G H & 7 F7 U * 8 ► 11 F8 Inbox (470) - van X ( 9 K ►► F9 bio 1108 chat O F10 P Account Summar 4) Tp SAVAGE X FENTY... Previous F11 11 + = { ļ Next> Mon Oct 24 11 Save and Exit F12 11 } + Upda del-
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